Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

If both the distinct roots of the equation $open vertical bar sin invisible function application x close vertical bar to the power of 2 end exponent plus open vertical bar sin invisible function application x close vertical bar plus b equals 0 blank$ in $blank open square brackets 0 comma pi close square brackets$ are real, then the values of $b$ are

$[- 2, 0]$
$(- 2, 0)$
$[- 2, 0)$
None of these

The correct answer is: $open parentheses negative 2 comma blank 0 close parentheses$

Given that $open vertical bar sin invisible function application x close vertical bar to the power of 2 end exponent plus open vertical bar sin invisible function application x close vertical bar plus b equals 0$
$rightwards double arrow open vertical bar sin invisible function application x close vertical bar equals fraction numerator negative 1 plus-or-minus square root of 1 minus 4 b end root over denominator 2 end fraction blank rightwards double arrow 0 less or equal than fraction numerator negative 1 plus-or-minus square root of 1 minus 4 b end root over denominator 2 end fraction less than 1 blank rightwards double arrow negative 2 less than b less than 0$

Related Questions to study

In triangle $A B C comma$ internal angle bisector $angle A$ makes an angle $theta$ with side $B C.$ The value of $sin invisible function application theta$ is equal to

In triangle $A B C comma$ internal angle bisector $angle A$ makes an angle $theta$ with side $B C.$ The value of $sin invisible function application theta$ is equal to

If $open parentheses 4 close parentheses to the power of log subscript 9 end subscript invisible function application 3 end exponent plus open parentheses 9 close parentheses to the power of log subscript 2 end subscript invisible function application 4 end exponent equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent comma$ then $x$ is equal to

If $open parentheses 4 close parentheses to the power of log subscript 9 end subscript invisible function application 3 end exponent plus open parentheses 9 close parentheses to the power of log subscript 2 end subscript invisible function application 4 end exponent equals open parentheses 10 close parentheses to the power of log subscript x end subscript invisible function application 83 end exponent comma$ then $x$ is equal to

The value of $log invisible function application a b minus log invisible function application open vertical bar b close vertical bar equals$

The value of $log invisible function application a b minus log invisible function application open vertical bar b close vertical bar equals$

parallel

If $alpha comma blank beta comma blank gamma comma blank delta$ are the smallest positive angles in ascending order of magnitude which have their sines equal to the positive quantity $k comma$ then the value of $4 sin invisible function application fraction numerator alpha over denominator 2 end fraction plus 3 sin invisible function application fraction numerator beta over denominator 2 end fraction plus 2 sin invisible function application fraction numerator gamma over denominator 2 end fraction plus sin invisible function application fraction numerator delta over denominator 2 end fraction$ is equal to

If $alpha comma blank beta comma blank gamma comma blank delta$ are the smallest positive angles in ascending order of magnitude which have their sines equal to the positive quantity $k comma$ then the value of $4 sin invisible function application fraction numerator alpha over denominator 2 end fraction plus 3 sin invisible function application fraction numerator beta over denominator 2 end fraction plus 2 sin invisible function application fraction numerator gamma over denominator 2 end fraction plus sin invisible function application fraction numerator delta over denominator 2 end fraction$ is equal to

The value of $x$ satisfying $square root of 3 to the power of negative 4 plus 2 log subscript square root of 5 end subscript invisible function application x end exponent equals 1 divided by 9$ is

The value of $x$ satisfying $square root of 3 to the power of negative 4 plus 2 log subscript square root of 5 end subscript invisible function application x end exponent equals 1 divided by 9$ is

In $blank increment A B C$ , if $b to the power of 2 end exponent plus c to the power of 2 end exponent equals 2 a to the power of 2 end exponent comma$ then value of $fraction numerator cot invisible function application A over denominator cot invisible function application B plus cot invisible function application C end fraction$ is

In $blank increment A B C$ , if $b to the power of 2 end exponent plus c to the power of 2 end exponent equals 2 a to the power of 2 end exponent comma$ then value of $fraction numerator cot invisible function application A over denominator cot invisible function application B plus cot invisible function application C end fraction$ is

parallel

If $log subscript 10 end subscript invisible function application open square brackets fraction numerator 1 over denominator 2 to the power of x end exponent plus blank x minus 1 end fraction close square brackets equals x open square brackets log subscript 10 end subscript invisible function application 5 minus 1 close square brackets comma blank t h e n blank x equals$

If $log subscript 10 end subscript invisible function application open square brackets fraction numerator 1 over denominator 2 to the power of x end exponent plus blank x minus 1 end fraction close square brackets equals x open square brackets log subscript 10 end subscript invisible function application 5 minus 1 close square brackets comma blank t h e n blank x equals$

r triangle $A B C comma blank R equals 5 divided by 2 blank$ and $blank r equals 1.$ Let $I$ be the incentre of the triangle and $D comma blank E$ and $blank F$ be the feet of the perpendiculars from $I blank$ to $blank B C comma blank C A blank$ and $blank A B comma$ respectively. The value of $fraction numerator I D cross times I E cross times I F over denominator I A cross times I B cross times I C end fraction blank$ is equal to

r triangle $A B C comma blank R equals 5 divided by 2 blank$ and $blank r equals 1.$ Let $I$ be the incentre of the triangle and $D comma blank E$ and $blank F$ be the feet of the perpendiculars from $I blank$ to $blank B C comma blank C A blank$ and $blank A B comma$ respectively. The value of $fraction numerator I D cross times I E cross times I F over denominator I A cross times I B cross times I C end fraction blank$ is equal to

any $increment A B C comma$ the value of $a open parentheses b to the power of 2 end exponent plus c to the power of 2 end exponent close parentheses cos invisible function application A plus b left parenthesis c to the power of 2 end exponent plus a to the power of 2 end exponent right parenthesis cos invisible function application B plus c left parenthesis a to the power of 2 end exponent plus b to the power of 2 end exponent right parenthesis cos invisible function application C equals$

any $increment A B C comma$ the value of $a open parentheses b to the power of 2 end exponent plus c to the power of 2 end exponent close parentheses cos invisible function application A plus b left parenthesis c to the power of 2 end exponent plus a to the power of 2 end exponent right parenthesis cos invisible function application B plus c left parenthesis a to the power of 2 end exponent plus b to the power of 2 end exponent right parenthesis cos invisible function application C equals$

parallel

$fraction numerator sin invisible function application x over denominator sin invisible function application y end fraction equals fraction numerator 1 over denominator 2 end fraction comma fraction numerator cos invisible function application x over denominator cos invisible function application y end fraction equals fraction numerator 3 over denominator 2 end fraction blank w h e r e blank x comma blank y blank element of open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses comma blank t h e n blank t h e blank v a l u e blank o f blank left parenthesis x plus y right parenthesis blank i s blank e q u a l blank t o$

$fraction numerator sin invisible function application x over denominator sin invisible function application y end fraction equals fraction numerator 1 over denominator 2 end fraction comma fraction numerator cos invisible function application x over denominator cos invisible function application y end fraction equals fraction numerator 3 over denominator 2 end fraction blank w h e r e blank x comma blank y blank element of open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses comma blank t h e n blank t h e blank v a l u e blank o f blank left parenthesis x plus y right parenthesis blank i s blank e q u a l blank t o$

$tan invisible function application 3 theta plus tan invisible function application theta equals 2 tan invisible function application 2 theta$ , then $blank theta$ is equal to $open parentheses n element of Z close parentheses$

$tan invisible function application 3 theta plus tan invisible function application theta equals 2 tan invisible function application 2 theta$ , then $blank theta$ is equal to $open parentheses n element of Z close parentheses$

e number of solutions of $blank not stretchy sum from r equals 1 to 5 of cos invisible function application r x equals 5$ in the interval $blank open square brackets 0 comma blank 2 pi close square brackets blank$ is

e number of solutions of $blank not stretchy sum from r equals 1 to 5 of cos invisible function application r x equals 5$ in the interval $blank open square brackets 0 comma blank 2 pi close square brackets blank$ is

parallel

Member of roots of $open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus sin invisible function application 2 theta close parentheses equals 1 plus tan invisible function application theta$ for $blank theta element of open square brackets 0 comma blank 2 pi close square brackets$ is

Member of roots of $open parentheses 1 minus tan invisible function application theta close parentheses open parentheses 1 plus sin invisible function application 2 theta close parentheses equals 1 plus tan invisible function application theta$ for $blank theta element of open square brackets 0 comma blank 2 pi close square brackets$ is

r $blank n element of Z comma blank$ the general solution of $open parentheses square root of 3 minus 1 close parentheses sin invisible function application theta plus open parentheses square root of 3 plus 1 close parentheses cos invisible function application theta equals 2 blank$ is $open parentheses n element of Z close parentheses$

r $blank n element of Z comma blank$ the general solution of $open parentheses square root of 3 minus 1 close parentheses sin invisible function application theta plus open parentheses square root of 3 plus 1 close parentheses cos invisible function application theta equals 2 blank$ is $open parentheses n element of Z close parentheses$

e set of all $x$ in $open parentheses fraction numerator – pi over denominator 2 end fraction comma fraction numerator pi over denominator 2 end fraction close parentheses blank$ satisfying $blank open vertical bar 4 sin invisible function application x minus 1 close vertical bar less than square root of 5$ is given by

e set of all $x$ in $open parentheses fraction numerator – pi over denominator 2 end fraction comma fraction numerator pi over denominator 2 end fraction close parentheses blank$ satisfying $blank open vertical bar 4 sin invisible function application x minus 1 close vertical bar less than square root of 5$ is given by

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.