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Question

If $n open parentheses A close parentheses equals 4 comma blank n open parentheses B close parentheses equals 3 comma blank n open parentheses A cross times B cross times C close parentheses equals 240$ , then $n left parenthesis C right parenthesis$ is equal to

288
1
12
2

The correct answer is: 2

$because blank n open parentheses A cross times B cross times C close parentheses equals n left parenthesis A right parenthesis cross times n left parenthesis B right parenthesis cross times n left parenthesis C right parenthesis$
$therefore blank n open parentheses C close parentheses equals fraction numerator 24 over denominator 4 cross times 3 end fraction equals 2$

Related Questions to study

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If $A$ and $B$ are two sets such that $n open parentheses A close parentheses equals 7 comma n open parentheses B close parentheses equals 6$ and $open parentheses A intersection B close parentheses not equal to ϕ.$ Then the greatest possible value of $n open parentheses A blank capital delta blank B close parentheses comma$ is

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