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Maths-

General

Easy

Question

If $n open parentheses u close parentheses equals 100 comma n open parentheses A close parentheses equals 50 comma blank n open parentheses B close parentheses equals 20$ and $n open parentheses A intersection B close parentheses equals 10 comma$ then $n open curly brackets open parentheses A union B close parentheses to the power of c end exponent close curly brackets$

60
30
40
20

The correct answer is: 40

$n open parentheses open parentheses A union B close parentheses to the power of c end exponent close curly brackets equals n open parentheses U close parentheses minus n left parenthesis A union B right parenthesis$
$equals n open parentheses U close parentheses minus left curly bracket n open parentheses A close parentheses plus n open parentheses B close parentheses minus n left parenthesis A intersection B right parenthesis right curly bracket$
$equals 100 minus open parentheses 50 plus 20 minus 10 close parentheses equals 40$

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