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Physics-

General

Easy

Question

A straight wire of length $L$ is bent into a semicircle. It is moved in a uniform magnetic field with speed $v$ with diameter perpendicular to the field. The induced emf between the ends of the wire is

$B L v$
$2 B L v$
$2 π B L v$
$\frac{2 B v L}{π}$

The correct answer is: $fraction numerator 2 B v L over denominator pi end fraction$

Induced emf $e equals B v l rightwards double arrow e equals B v open parentheses 2 R close parentheses equals fraction numerator 2 B v L over denominator pi end fraction$

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