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Maths-

General

Easy

Question

If $tan invisible function application theta equals square root of a over b end root$ where a, b are positive reals then the value of $space sin invisible function application theta sec 7 theta plus cos invisible function application theta cosec to the power of blank 7 theta$ is -

$\frac{(a + b)^{3} (a^{4} + b^{4})}{(a b)^{7 / 2}}$
$\frac{(a + b)^{3} (a^{4} - b^{4})}{(a b)^{7 / 2}}$
$\frac{(a + b)^{3} (b^{4} - a^{4})}{(a b)^{7 / 2}}$
$- \frac{(a + b)^{3} (a^{4} + b^{4})}{(a b)^{7 / 2}}$

The correct answer is: $fraction numerator left parenthesis a plus b right parenthesis cubed open parentheses a to the power of 4 plus b to the power of 4 close parentheses over denominator left parenthesis a b right parenthesis to the power of 7 divided by 2 end exponent end fraction$

Related Questions to study

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

The expression $fraction numerator sin invisible function application 22 to the power of ring operator cos invisible function application 8 to the power of ring operator plus cos invisible function application 158 to the power of ring operator cos invisible function application 98 to the power of ring operator over denominator sin invisible function application 23 to the power of ring operator cos invisible function application 7 to the power of ring operator plus cos invisible function application 157 to the power of ring operator cos invisible function application 97 to the power of ring operator end fraction$ when simplified reduces to -

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

If A = $sin invisible function application fraction numerator 2 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 4 pi over denominator 7 end fraction plus sin invisible function application fraction numerator 8 pi over denominator 7 end fraction$ and B = $cos invisible function application fraction numerator 2 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 4 pi over denominator 7 end fraction plus cos invisible function application fraction numerator 8 pi over denominator 7 end fraction$ then $square root of A squared plus B squared end root$ is equal to

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

If $tan invisible function application B equals fraction numerator n sin invisible function application A cos invisible function application A over denominator 1 minus n cos squared invisible function application A end fraction$ then tan (A + B) equals

parallel

If x + y = 3 – cos4 $theta$ and x – y = 4 sin2 $theta$ then

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Which of the following is correct ?

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The value of the expression $open parentheses 1 plus cos invisible function application pi over 10 close parentheses open parentheses 1 plus cos invisible function application fraction numerator 3 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 7 pi over denominator 10 end fraction close parentheses open parentheses 1 plus cos invisible function application fraction numerator 9 pi over denominator 10 end fraction close parentheses$ is

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