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General
Easy

Question

If y = (1+x to the power of 2 end exponent right parenthesis T a n to the power of negative 1 end exponent x minus x blankthen fraction numerator text dy end text over denominator text dx end text end fraction =

  1. 0    
  2. left parenthesis 1 plus x to the power of 2 end exponent right parenthesis t a n to the power of negative 1 end exponent x minus x    
  3. 2 x t a n to the power of negative 1 end exponent x    
  4. x t a n to the power of negative 1 end exponent x    

The correct answer is: 2 x t a n to the power of negative 1 end exponent x



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