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Maths-

General

Easy

Question

$not stretchy integral subscript blank superscript blank fraction numerator 2 x plus blank s i n blank 2 x over denominator 1 plus blank c o s blank 2 x end fraction d x equals$

$x s i n 2 x + c$
$- x t a n x + c$
$x s e c x + c$
$x t a n x + c$

The correct answer is: $x blank t a n blank x plus c$

$not stretchy integral subscript blank superscript blank fraction numerator 2 x plus s i n 2 x over denominator 1 plus c o s 2 x end fraction d x$ $equals not stretchy integral subscript blank superscript blank fraction numerator 2 x plus 2 s i n x c o s x over denominator 2 c o s to the power of 2 end exponent x end fraction d x$
$equals not stretchy integral subscript blank superscript blank left parenthesis x s e c to the power of 2 end exponent x plus blank t a n blank x right parenthesis d x$
$equals x blank t a n blank x plus c$
$not stretchy integral subscript blank superscript blank left parenthesis x f to the power of ´ end exponent left parenthesis x right parenthesis plus f left parenthesis x right parenthesis right parenthesis d x equals x f left parenthesis x right parenthesis plus c right parenthesis$
$x blank t a n blank x plus c$

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