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Maths-

General

Easy

Question

Let $A subscript 1 end subscript comma A subscript 2 end subscript comma A subscript 3 end subscript horizontal ellipsis comma A subscript 100 end subscript$ be 100 sets such that $n open parentheses A subscript i end subscript close parentheses equals i plus 1$ and $A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript subset of A subscript 100 end subscript comma$ then $not stretchy ⋃ from i equals 1 to 100 of A subscript i end subscript$ contains… elements

99
100
101
102

The correct answer is: 101

We have,
$A subscript 1 end subscript subset of A subscript 2 end subscript subset of A subscript 3 end subscript subset of horizontal ellipsis subset of A subscript 100 end subscript$
$therefore not stretchy ⋃ from i equals 1 to 100 of A subscript i end subscript equals A subscript 100 end subscript rightwards double arrow n open parentheses not stretchy ⋃ from i equals 1 to 100 of A subscript i end subscript close parentheses equals n open parentheses A subscript 100 end subscript close parentheses equals 101$

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