Maths-
General
Easy

Question

Letf open parentheses x close parentheses equals not stretchy integral e to the power of x end exponent open parentheses x minus 1 close parentheses left parenthesis x minus 2 right parenthesis d x. Then, f decreases in the interval

  1. open parentheses negative infinity comma blank minus 2 close parentheses  
  2. open parentheses negative 2 comma blank minus 1 close parentheses  
  3. left parenthesis 1 comma blank 2 right parenthesis  
  4. left parenthesis 2 comma blank infinity right parenthesis  

The correct answer is: left parenthesis 1 comma blank 2 right parenthesis


    Given that, f open parentheses x close parentheses equals not stretchy integral e to the power of x end exponent open parentheses x minus 1 close parentheses open parentheses x minus 2 close parentheses d x
    On differentiating w.r.t. x, we get

    f to the power of ´ ´ end exponent open parentheses x close parentheses equals e to the power of x end exponent open parentheses x minus 1 close parentheses open parentheses x minus 2 close parentheses

    Since, f left parenthesis x right parenthesis is decreasing

    therefore blank f to the power of ´ ´ end exponent open parentheses x close parentheses less than 0 blank rightwards double arrow blank e to the power of x end exponent open parentheses x minus 1 close parentheses open parentheses x minus 2 close parentheses less than 0

    rightwards double arrow open parentheses x minus 1 close parentheses open parentheses x minus 2 close parentheses less than 0 blank rightwards double arrow blank 1 less than x less than 2

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