Physics-
General
Easy

Question

A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 cross times 10 to the power of negative 3 end exponent W b. The self-inductance of the solenoid is

  1. 1.0 henry  
  2. 4.0 henry  
  3. 2.5 henry  
  4. 2.0 henry  

The correct answer is: 1.0 henry


    N ϕ equals L i rightwards double arrow L equals fraction numerator N ϕ over denominator i end fraction equals fraction numerator 500 cross times 4 rightwards double arrow 10 to the power of negative 3 end exponent over denominator 2 end fraction equals 1 blank h e n r y

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