Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Let $X$ be a family of sets and $R$ be a relation on $X$ defined by $´ A$ is disjoint from $B to the power of ´ end exponent.$ Then, $R$ is

Reflexive
Symmetric
Antisymmetric
Transitive

The correct answer is: Symmetric

Clearly, the relation is symmetric but it is neither reflexive nor transitive

Related Questions to study

Let $L$ denote the set of all straight lines in a plane. Let a relation $R$ be defined by $alpha blank R blank beta left right double arrow alpha perpendicular beta comma alpha comma beta element of L.$ Then $R$ is

Let $L$ denote the set of all straight lines in a plane. Let a relation $R$ be defined by $alpha blank R blank beta left right double arrow alpha perpendicular beta comma alpha comma beta element of L.$ Then $R$ is

Suppose $A subscript 1 end subscript comma blank A subscript 2 end subscript comma horizontal ellipsis comma A subscript 30 end subscript$ are thirty sets, each having 5 elements and $B subscript 1 end subscript comma blank B subscript 2 end subscript comma blank horizontal ellipsis comma blank B subscript n end subscript$ are $n$ sets each with 3 elements, let
$not stretchy ⋃ subscript i equals 1 end subscript superscript 30 end superscript A subscript i end subscript equals not stretchy ⋃ subscript j equals 1 end subscript superscript n end superscript B subscript j end subscript equals S$ and each element of $S$ belongs to exactly 10 of the $A subscript i end subscript$ 's and exactly 9 of the $B subscript j end subscript$ 's. Then, $n$ is equal to

Suppose $A subscript 1 end subscript comma blank A subscript 2 end subscript comma horizontal ellipsis comma A subscript 30 end subscript$ are thirty sets, each having 5 elements and $B subscript 1 end subscript comma blank B subscript 2 end subscript comma blank horizontal ellipsis comma blank B subscript n end subscript$ are $n$ sets each with 3 elements, let
$not stretchy ⋃ subscript i equals 1 end subscript superscript 30 end superscript A subscript i end subscript equals not stretchy ⋃ subscript j equals 1 end subscript superscript n end superscript B subscript j end subscript equals S$ and each element of $S$ belongs to exactly 10 of the $A subscript i end subscript$ 's and exactly 9 of the $B subscript j end subscript$ 's. Then, $n$ is equal to

Let $P equals open curly brackets open parentheses x comma y close parentheses vertical line x to the power of 2 end exponent plus y to the power of 2 end exponent equals 1 comma x comma y element of R close curly brackets.$ Then, $P$ is

Let $P equals open curly brackets open parentheses x comma y close parentheses vertical line x to the power of 2 end exponent plus y to the power of 2 end exponent equals 1 comma x comma y element of R close curly brackets.$ Then, $P$ is

parallel

Three sets $A comma blank B comma blank C$ are such that $A equals B intersection C$ and $B equals C intersection A$ , then

Three sets $A comma blank B comma blank C$ are such that $A equals B intersection C$ and $B equals C intersection A$ , then

If $A$ is a non-empty set, then which of the following is false?
$p blank colon$ Every reflexive relation is a symmetric relation
$q blank colon$ Every antisymmetric relation is reflexive
Which of the following is/are true?

If $A$ is a non-empty set, then which of the following is false?
$p blank colon$ Every reflexive relation is a symmetric relation
$q blank colon$ Every antisymmetric relation is reflexive
Which of the following is/are true?

If $n open parentheses A close parentheses equals 4 comma blank n open parentheses B close parentheses equals 3 comma blank n open parentheses A cross times B cross times C close parentheses equals 240$ , then $n left parenthesis C right parenthesis$ is equal to

If $n open parentheses A close parentheses equals 4 comma blank n open parentheses B close parentheses equals 3 comma blank n open parentheses A cross times B cross times C close parentheses equals 240$ , then $n left parenthesis C right parenthesis$ is equal to

parallel

If $A$ and $B$ are two sets such that $n open parentheses A close parentheses equals 7 comma n open parentheses B close parentheses equals 6$ and $open parentheses A intersection B close parentheses not equal to ϕ.$ Then the greatest possible value of $n open parentheses A blank capital delta blank B close parentheses comma$ is

If $A$ and $B$ are two sets such that $n open parentheses A close parentheses equals 7 comma n open parentheses B close parentheses equals 6$ and $open parentheses A intersection B close parentheses not equal to ϕ.$ Then the greatest possible value of $n open parentheses A blank capital delta blank B close parentheses comma$ is

The relation “is a factor of” on the set $N$ of all natural numbers is not

The relation “is a factor of” on the set $N$ of all natural numbers is not

The value of $open parentheses A union B union C close parentheses intersection open parentheses A intersection B to the power of C end exponent intersection C to the power of C end exponent close parentheses to the power of C end exponent intersection C to the power of C end exponent$ is

The value of $open parentheses A union B union C close parentheses intersection open parentheses A intersection B to the power of C end exponent intersection C to the power of C end exponent close parentheses to the power of C end exponent intersection C to the power of C end exponent$ is

parallel

Let $A equals open curly brackets open parentheses x comma y close parentheses colon y equals e to the power of x end exponent comma x element of R close curly brackets comma$
$B equals open curly brackets open parentheses x comma y close parentheses colon y equals e to the power of negative x end exponent comma x element of R close curly brackets.$ Then,

Let $A equals open curly brackets open parentheses x comma y close parentheses colon y equals e to the power of x end exponent comma x element of R close curly brackets comma$
$B equals open curly brackets open parentheses x comma y close parentheses colon y equals e to the power of negative x end exponent comma x element of R close curly brackets.$ Then,

The relation $R equals open curly brackets open parentheses 13 close parentheses comma left parenthesis 35 right parenthesis close curly brackets$ is defined on the set with minimum number of elements of natural numbers. The minimum number of elements to be included in $R$ so that $R$ is an equivalence relation, is

The relation $R equals open curly brackets open parentheses 13 close parentheses comma left parenthesis 35 right parenthesis close curly brackets$ is defined on the set with minimum number of elements of natural numbers. The minimum number of elements to be included in $R$ so that $R$ is an equivalence relation, is

If $n open parentheses u close parentheses equals 100 comma n open parentheses A close parentheses equals 50 comma blank n open parentheses B close parentheses equals 20$ and $n open parentheses A intersection B close parentheses equals 10 comma$ then $n open curly brackets open parentheses A union B close parentheses to the power of c end exponent close curly brackets$

If $n open parentheses u close parentheses equals 100 comma n open parentheses A close parentheses equals 50 comma blank n open parentheses B close parentheses equals 20$ and $n open parentheses A intersection B close parentheses equals 10 comma$ then $n open curly brackets open parentheses A union B close parentheses to the power of c end exponent close curly brackets$

parallel

If $A equals open curly brackets open parentheses x comma y close parentheses blank colon y equals fraction numerator 4 over denominator x end fraction comma x not equal to 0 close curly brackets$ and
$B equals open curly brackets open parentheses x comma y close parentheses colon x to the power of 2 end exponent plus y to the power of 2 end exponent equals 8 comma x comma y element of R close curly brackets$ , then

If $A equals open curly brackets open parentheses x comma y close parentheses blank colon y equals fraction numerator 4 over denominator x end fraction comma x not equal to 0 close curly brackets$ and
$B equals open curly brackets open parentheses x comma y close parentheses colon x to the power of 2 end exponent plus y to the power of 2 end exponent equals 8 comma x comma y element of R close curly brackets$ , then

If $A$ and $B$ are two sets, then $A minus left parenthesis A minus B right parenthesis$ is equal to

If $A$ and $B$ are two sets, then $A minus left parenthesis A minus B right parenthesis$ is equal to

A class has 175 students. The following data shows the number of students opting one or more subjects. Mathematics 100; Physics 70; Chemistry 40; Mathematics and Physics 30; Mathematics and Chemistry 28; Physics and Chemistry 23; Mathematics, Physics and Chemistry 18. Hoe many students have offered Mathematics alone?

A class has 175 students. The following data shows the number of students opting one or more subjects. Mathematics 100; Physics 70; Chemistry 40; Mathematics and Physics 30; Mathematics and Chemistry 28; Physics and Chemistry 23; Mathematics, Physics and Chemistry 18. Hoe many students have offered Mathematics alone?

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.