Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

Let $Y equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma blank A open curly brackets 1 comma blank 2 close curly brackets comma blank B equals left curly bracket 3 comma blank 4 comma blank 5 right curly bracket$ and $ϕ$ denotes null set. If $left parenthesis A cross times B right parenthesis$ denotes cartesian product of the sets $A$ and $B$ ; then $open parentheses Y cross times A close parentheses intersection left parenthesis Y cross times B right parenthesis$ is

$Y$
$A$
$B$
$ϕ$

The correct answer is: $ϕ$

$open parentheses Y cross times A close parentheses equals left curly bracket open parentheses 1 comma blank 1 close parentheses comma blank open parentheses 1 comma blank 2 close parentheses comma blank open parentheses 2 comma blank 1 close parentheses comma blank open parentheses 2 comma blank 2 close parentheses comma$
$open parentheses 3 comma blank 1 close parentheses comma blank open parentheses 3 comma blank 2 close parentheses comma blank open parentheses 4 comma blank 1 close parentheses comma blank open parentheses 4 comma blank 2 close parentheses comma blank open parentheses 5 comma blank 1 close parentheses comma blank left parenthesis 5 comma blank 2 right parenthesis right curly bracket$
And $open parentheses Y cross times B close parentheses equals left curly bracket open parentheses 1 comma blank 3 close parentheses comma blank open parentheses 1 comma blank 4 close parentheses comma blank open parentheses 1 comma blank 5 close parentheses comma blank open parentheses 2 comma blank 3 close parentheses comma$
$open parentheses 2 comma blank 4 close parentheses comma blank open parentheses 2 comma blank 5 close parentheses comma blank open parentheses 3 comma blank 3 close parentheses comma blank open parentheses 3 comma blank 4 close parentheses comma blank open parentheses 3 comma blank 5 close parentheses comma blank open parentheses 4 comma blank 3 close parentheses comma$
$open parentheses 4 comma blank 4 close parentheses comma blank open parentheses 4 comma blank 5 close parentheses comma blank open parentheses 5 comma blank 3 close parentheses comma blank open parentheses 5 comma blank 4 close parentheses comma blank left parenthesis 5 comma blank 5 right parenthesis right curly bracket$
$therefore open parentheses Y cross times A close parentheses intersection open parentheses Y cross times B close parentheses equals ϕ$

Related Questions to study

If $A$ and $B$ are two given sets, then $A intersection open parentheses A intersection B close parentheses to the power of c end exponent$ is equal to

If $A$ and $B$ are two given sets, then $A intersection open parentheses A intersection B close parentheses to the power of c end exponent$ is equal to

The relation ‘is subset of’ on the power set $P left parenthesis A right parenthesis$ of a set $A$ is

The relation ‘is subset of’ on the power set $P left parenthesis A right parenthesis$ of a set $A$ is

In Q.No. $6 comma not stretchy ⋂ from n equals 3 to 10 of A subscript n end subscript equals$

In Q.No. $6 comma not stretchy ⋂ from n equals 3 to 10 of A subscript n end subscript equals$

parallel

If $A equals open curly brackets p element of N colon p blank i s blank a blank p r i m e blank a n d blank p equals fraction numerator 7 n to the power of 2 end exponent plus 3 n plus 3 over denominator n end fraction blank f o r blank s o m e blank n element of N close curly brackets comma$ then the number of elements in the set $A comma$ is

If $A equals open curly brackets p element of N colon p blank i s blank a blank p r i m e blank a n d blank p equals fraction numerator 7 n to the power of 2 end exponent plus 3 n plus 3 over denominator n end fraction blank f o r blank s o m e blank n element of N close curly brackets comma$ then the number of elements in the set $A comma$ is

Let $U$ be the universal set for sets $A$ and $B$ such that $n open parentheses A close parentheses equals 200 comma n open parentheses B close parentheses equals 300$ and $n open parentheses A intersection B close parentheses equals 100.$ Then, $n left parenthesis A ´ intersection B ´ right parenthesis$ is equal to 300, provided that $n left parenthesis blank U right parenthesis$ is equal to

Let $U$ be the universal set for sets $A$ and $B$ such that $n open parentheses A close parentheses equals 200 comma n open parentheses B close parentheses equals 300$ and $n open parentheses A intersection B close parentheses equals 100.$ Then, $n left parenthesis A ´ intersection B ´ right parenthesis$ is equal to 300, provided that $n left parenthesis blank U right parenthesis$ is equal to

If $A$ and $B$ are two sets, then $A intersection left parenthesis A union B right parenthesis$ equals

If $A$ and $B$ are two sets, then $A intersection left parenthesis A union B right parenthesis$ equals

parallel

Let $A equals open curly brackets 12 comma 34 close curly brackets comma$ and let $R equals left curly bracket open parentheses 22 close parentheses comma open parentheses 33 close parentheses comma open parentheses 44 close parentheses comma left parenthesis 12 right parenthesis right curly bracket$ be a relation on $A.$ Then, $R$ is

Let $A equals open curly brackets 12 comma 34 close curly brackets comma$ and let $R equals left curly bracket open parentheses 22 close parentheses comma open parentheses 33 close parentheses comma open parentheses 44 close parentheses comma left parenthesis 12 right parenthesis right curly bracket$ be a relation on $A.$ Then, $R$ is

$left curly bracket n open parentheses n plus 1 close parentheses open parentheses 2 n plus 1 close parentheses colon n element of Z right curly bracket subset of$

$left curly bracket n open parentheses n plus 1 close parentheses open parentheses 2 n plus 1 close parentheses colon n element of Z right curly bracket subset of$

Two points $P$ and $Q$ in a plane are related if $O P equals O Q comma$ where $O$ is a fixed point. This relation is

Two points $P$ and $Q$ in a plane are related if $O P equals O Q comma$ where $O$ is a fixed point. This relation is

parallel

The void relation on a set $A$ is

The void relation on a set $A$ is

If $A equals open curly brackets theta blank colon cos invisible function application theta greater than negative fraction numerator 1 over denominator 2 end fraction comma 0 less or equal than theta less or equal than pi close curly brackets$ and
$B equals open curly brackets theta blank colon sin invisible function application theta greater than fraction numerator 1 over denominator 2 end fraction comma fraction numerator pi over denominator 3 end fraction less or equal than theta less or equal than pi close curly brackets comma$ then

If $A equals open curly brackets theta blank colon cos invisible function application theta greater than negative fraction numerator 1 over denominator 2 end fraction comma 0 less or equal than theta less or equal than pi close curly brackets$ and
$B equals open curly brackets theta blank colon sin invisible function application theta greater than fraction numerator 1 over denominator 2 end fraction comma fraction numerator pi over denominator 3 end fraction less or equal than theta less or equal than pi close curly brackets comma$ then

Out of 800 boys in a school 224 played cricket, 240 played hockey and 336 played basketball. Of the total, 64 played both basketball and hockey; 80 played cricket and basketball and 40 played cricket and hockey; 24 played all the three games. The number of boys who did not play any game is

Out of 800 boys in a school 224 played cricket, 240 played hockey and 336 played basketball. Of the total, 64 played both basketball and hockey; 80 played cricket and basketball and 40 played cricket and hockey; 24 played all the three games. The number of boys who did not play any game is

parallel

If $A equals open curly brackets n colon fraction numerator n to the power of 3 end exponent plus 5 n to the power of 2 end exponent plus 2 over denominator n end fraction blank i s blank a n blank i n t e g e r blank a n d blank i t s e l f blank i s blank a n blank i n t e g e r close curly brackets comma$ then the number of elements in the set $A comma$ is

If $A equals open curly brackets n colon fraction numerator n to the power of 3 end exponent plus 5 n to the power of 2 end exponent plus 2 over denominator n end fraction blank i s blank a n blank i n t e g e r blank a n d blank i t s e l f blank i s blank a n blank i n t e g e r close curly brackets comma$ then the number of elements in the set $A comma$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma blank B equals left curly bracket a comma blank b right curly bracket$ , then $A cross times B$ mapped $A$ to $B$ is

If $A equals open curly brackets 1 comma blank 2 comma blank 3 close curly brackets comma blank B equals left curly bracket a comma blank b right curly bracket$ , then $A cross times B$ mapped $A$ to $B$ is

Statement 1: $1 to the power of 99 end exponent plus 2 to the power of 99 end exponent plus horizontal ellipsis plus 100 to the power of 99 end exponent$ is divisible by 10100
Statement 2: $a to the power of n end exponent plus b to the power of n end exponent$ is divisible by $a plus b$ if $n$ is odd

Statement 1: $1 to the power of 99 end exponent plus 2 to the power of 99 end exponent plus horizontal ellipsis plus 100 to the power of 99 end exponent$ is divisible by 10100
Statement 2: $a to the power of n end exponent plus b to the power of n end exponent$ is divisible by $a plus b$ if $n$ is odd

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.