Maths-
General
Easy
Question
Number of solutions of the equation Sin x + sin2x + sin3 x + sin4x + ……. Π= 2 where x Π[0,4Π], is
- 2
- 4
- 5
- 6
The correct answer is: 4
Sin x (1 + sin x + sin2 + ….. ) = 2
only in
there are 2 solution in [ 0,
]
And again we set 2 solution for same intervel in 
Total solutions are 4
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