Question
Suppose equation is f(x) – g(x) = 0 of f(x) = g(x) = y say, then draw the graphs of y = f(x) and y = g(x). If graph of y = f(x) and y = g(x) cuts at one, two, three, ...., no points, then number of solutions are one, two, three, ...., zero respectively.
The number of solutions of sin x = is
- 4
- 6
- 8
- none of these
Hint:
Here, equation f(x)−g(x)=0 or f(x)=g(x)=y says, then draw the graphs of y=f(x) and y=g(x). if graphs of y=f(x) and y=g(x) cuts at one, two, three, no points, then number of solutions are one, two, three, zero respectively.
The correct answer is: 6
Here, we have to find out number of solutions.
Firstly, we have given
Sinx = ,
We know that,
-1 ≤ sinx ≤ 1 so,
0 ≤ |x|/10 ≤ 1,
The, the curve on graph, X belongs to [ 0, 10]
From fig, f(x) = sinx and g(x) =, so it intersects 6 points
The number of solutions is 6.
The correct answer is 6.
In this question, we have drawn the graph. The number of intersections of both function fx and gx are the number solutions. Draw the graph carefully and find the intersection points.
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Statement-II : If sinA = sinB and cosA = cosB, then
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Statement-II : If sinA = sinB and cosA = cosB, then
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Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.
Statement-II : If sin x > 0, then
Statement-I : The equation sin(cos x) = cos(sin x) does not possess real roots.
Statement-II : If sin x > 0, then
Statement-I : In (0, ), the number of solutions of the equation is two
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Statement-I : In (0, ), the number of solutions of the equation is two
Statement-II : is not defined at
In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, it has 5 solutions, but tanθ &tan3θ are not defined at , , . respectively so it remains only 2.
Statement-I : If sin x + cos x = then
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In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, Start solving first Statement and try to prove it. Then solve the Statement-II. Always, the AM–GM inequality states that AM ≥ GM.
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Statement-II : AM ≥ GM
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Statement-I : The number of real solutions of the equation sin x = 2x + 2–x is zero
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Statement-I : The number of real solutions of the equation sin x = 2x + 2–x is zero
Statement-II : Since |sin x| ≤ 1
In this question, we have to find the statements are the correct or not and statement 2 is correct explanation or not, is same as assertion and reason. Here, -1 ≤ sinx ≤ 1 for all value, remember that.
if
if
if
if
if
if
if
if
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In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.
if
In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.