$sin squared space x minus cos space 2 x equals 2 minus sin space 2 x$ if

$cos space 15 x equals sin space 5 x$ if

$sin space x plus sin space 2 x plus sin space 3 x equals cos space x plus cos space 2 x plus cos space 3 x$ if

$4 sin to the power of 4 space x plus cos to the power of 4 space x equals 1$ if

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.

$4 sin to the power of 4 space x plus cos to the power of 4 space x equals 1$ if

In this question, we have to find the general solution of x. Here more than one option will correct. Remember the rules for finding the general solution.

Number of ordered pairs (a, x) satisfying the equation $sec squared space left parenthesis a plus 2 right parenthesis x plus a squared minus 1 equals 0 semicolon minus pi less than x less than pi$ is

The general solution of the equation, $fraction numerator 1 minus sin space x plus midline horizontal ellipsis comma plus left parenthesis negative 1 right parenthesis to the power of n sin to the power of n space x plus midline horizontal ellipsis straight infinity over denominator 1 plus sin space x plus midline horizontal ellipsis plus sin to the power of n space x plus midline horizontal ellipsis straight infinity end fraction equals fraction numerator 1 minus cos space 2 x over denominator 1 plus cos space 2 x end fraction$ is :

Chemistry-

The noble gas used in atomic reactor ,is

Chemistry-General

chemistry-

Which compound does not give $N H subscript 3$ on heating?

chemistry-General

In the interval $open square brackets negative pi over 2 comma pi over 2 close square brackets$ the equation $log subscript sin space theta end subscript space left parenthesis cos space 2 theta right parenthesis equals 2$ has

In this question, we have to find type of solution, here, we know if $log subscript a b equals c$ then we can take antilog, b = c^a, and cos² θ = 1 – 2 sin² θ . Remember these terms and find the solution easily.

In the interval $open square brackets negative pi over 2 comma pi over 2 close square brackets$ the equation $log subscript sin space theta end subscript space left parenthesis cos space 2 theta right parenthesis equals 2$ has

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction minus 2 tan space theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket comma$ ,then

In this question, we have to find the where is θ lies. Here, always true for sinx ≥ 0 otherwise it is true for x=0, $straight pi over 2$ , $fraction numerator 3 straight pi over denominator 2 end fraction$ ,2π and since we also need x≠ $straight pi over 2$ , $fraction numerator 3 straight pi over denominator 2 end fraction$ for tanx and x≠0,2π for cotx all the solutions.

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of open parentheses 1 plus cot squared space theta close parentheses end root end fraction minus 2 tan space theta cot space theta equals negative 1 comma theta element of left square bracket 0 comma 2 pi right square bracket comma$ ,then

Number of solutions of the equation $cos space 6 x plus tan squared space x plus cos space 6 x times tan squared space x equals 1$ in the interval [0, 2 $straight pi$ ] is :

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of 1 plus cot 2 space theta end root end fraction minus 2 tan space theta cot space theta equals negative 1$ ,then

In this question, we have given equation, where we have to find where the θ belongs. For all value of sin θ cos θ = $fraction numerator 1 over denominator square root of 2 end fraction$ so θ always lies between ( 0 , $straight pi over 2$ ) .

If $fraction numerator sin cubed space theta minus cos cubed space theta over denominator sin space theta minus cos space theta end fraction minus fraction numerator cos begin display style space end style theta over denominator square root of 1 plus cot 2 space theta end root end fraction minus 2 tan space theta cot space theta equals negative 1$ ,then

If $6 cos space 2 theta plus 2 cos squared space theta divided by 2 plus 2 sin squared space theta equals 0 comma negative pi less than theta less than pi comma text then end text theta equals$

The most general solution of the equations $tan space theta equals negative 1 comma cos space theta equals 1 divided by square root of 2$ is

The general solution of the equation, $2 cot space theta over 2 equals left parenthesis 1 plus co t space theta right parenthesis squared$ is