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Maths-

General

Easy

Question

The arrangement of the following in ascending order of angle of rotation to eliminate xy term in the following equations.
i) 2 $text x end text to the power of 2 end exponent$ +5xy+2 $text y end text to the power of 2 end exponent$ +5x+7y+1=0
ii) 2 $text x end text to the power of 2 end exponent$ + $square root of text 3 end text end root$ xy+3 $text y end text to the power of 2 end exponent$ = 9
iii) 9 $x to the power of 2 end exponent$ +2 $square root of text 3 end text end root$ xy+7 $text y end text to the power of 2 end exponent$ = 10

C, A, B
B, A, C
A, B, C
C, B, A

The correct answer is: C, A, B

$theta equals blank fraction numerator 1 over denominator 2 end fraction blank t a n to the power of negative 1 end exponent open parentheses fraction numerator 2 h over denominator a minus b end fraction close parentheses$
$text i) end text theta equals fraction numerator 1 over denominator 2 end fraction blank t a n to the power of negative 1 end exponent open parentheses fraction numerator 5 over denominator 2 minus 2 end fraction close parentheses equals text end text 45 to the power of 0 end exponent$
$text ii) end text theta equals fraction numerator 1 over denominator 2 end fraction blank t a n to the power of negative 1 end exponent open parentheses fraction numerator square root of text 3 end text end root over denominator 2 minus 3 end fraction close parentheses equals text end text minus 30 to the power of 0 end exponent$
$theta text = end text 360 to the power of 0 end exponent minus 30 to the power of 0 end exponent equals 3 30 to the power of 0 end exponent$
$text iii) end text theta equals fraction numerator 1 over denominator 2 end fraction blank t a n to the power of negative 1 end exponent open parentheses fraction numerator 2 square root of text 3 end text end root over denominator 2 end fraction close parentheses equals text end text 30 to the power of 0 end exponent$

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