Physics-
General
Easy

Question

In a parabola spectrograph, the velocities of four positive ions P,Q,R and S are v1, v2, v3 and v4 respectively

  1. v subscript 1 end subscript greater than v subscript 2 end subscript greater than v subscript 3 end subscript greater than v subscript 4 end subscript    
  2. v subscript 1 end subscript less than v subscript 2 end subscript less than v subscript 3 end subscript less than v subscript 4 end subscript    
  3. v subscript 1 end subscript equals v subscript 2 end subscript equals v subscript 3 end subscript equals v subscript 4 end subscript    
  4. v subscript 1 end subscript less than less than v subscript 2 end subscript greater than v subscript 3 end subscript less than v subscript 4 end subscript    

The correct answer is: v subscript 1 end subscript greater than v subscript 2 end subscript greater than v subscript 3 end subscript greater than v subscript 4 end subscript


    because   x proportional to fraction numerator 1 over denominator v to the power of 2 end exponent end fraction. The ion whose deflection is less, its velocity will be more. From the curve x subscript 1 end subscript less than x subscript 2 end subscript less than x subscript 3 end subscript less than x subscript 4 end subscript, therefore v subscript 1 end subscript greater than v subscript 2 end subscript greater than v subscript 3 end subscript greater than v subscript 4 end subscript.

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