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The cartesian equation of $r squared c o s space 2 theta equals a squared$ is

$x^{2} + y^{2} = a^{2}$
$x^{2} - y^{2} = a^{2}$
$y^{2} - x^{2} = a^{2}$
$x^{2} + y^{2} + a^{2} = 0$

hint Hint:

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. Here we have to find the cartesian equation of $r squared c o s space 2 theta equals a squared$ .

The correct answer is: $x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent$

A quadratic equation, or sometimes just quadratics, is a polynomial equation with a maximum degree of two. It takes the following form:
ax² + bx + c = 0
where a, b, and c are constant terms and x is the unknown variable.
Now we have given the equation as $r squared c o s space 2 theta equals a squared$ .
Now we know that:
$cos space 2 theta equals cos squared theta minus sin squared theta$ .
So applying this, we get:
$r squared left parenthesis cos squared theta minus sin squared theta right parenthesis equals a squared$
Now lets substitute x= $r cos θ and y = r sin θ, we get:$
$r squared cos squared theta minus r squared sin squared theta equals a squared x squared minus y squared equals a squared$

Here we used the concept of quadratic equations and solved the problem. We also understood the concept of trigonometric ratios and used the formula to find the equation. So the equation is $x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent$ .

The castesian equation of $r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p$ is

Here we used the concept of quadratic equations and solved the problem. We also understood the concept of trigonometric ratios and used the formula to find the equation. So the equation is $x c o s space alpha plus y s i n space alpha equals p$ .

The castesian equation of $r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p$ is

Maths-General

Here we used the concept of quadratic equations and solved the problem. We also understood the concept of trigonometric ratios and used the formula to find the equation. So the equation is $x c o s space alpha plus y s i n space alpha equals p$ .

General

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The equation of the directrix of the conic whose length of the latusrectum is 5 and eccenticity is 1/2 is

maths-General

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maths-

The equation of the directrix of the conic $r C o s to the power of 2 end exponent invisible function application open parentheses fraction numerator theta over denominator 2 end fraction close parentheses equals 5$ is

maths-General

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A small source of sound moves on a circle as shown in the figure and an observer is standing on $O.$ Let $n subscript 1 end subscript comma n subscript 2 end subscript$ and $n subscript 3 end subscript$ be the frequencies heard when the source is at $A comma blank B blank$ and $C$ respectively. Then

physics-General

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In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

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Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

physics-General

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A is a set containing n elements. A subset P₁ is chosen, and A is reconstructed by replacing the elements of P₁. The same process is repeated for subsets P₁, P₂, … , P_m, with m > 1. The Number of ways of choosing P₁, P₂, …, P_m so that P₁ $union$ P₂ $union$ … $union$ P_m= A is -

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The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

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The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

Here we used the concept of cartesian lines and some trigonometric terms to solve. With the help of slope we identified the angle between them. Hence, these lines are perpendicular so the angle between them is $9 0 degrees.$

The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

Maths-General

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The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

maths-General

General

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The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is

maths-General

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The cartesian equation of is

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. Here we have to find the cartesian equation of .

The correct answer is:

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A small source of sound moves on a circle as shown in the figure and an observer is standing on Let and be the frequencies heard when the source is at and respectively. Then

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A is a set containing n elements. A subset P1 is chosen, and A is reconstructed by replacing the elements of P1. The same process is repeated for subsets P1, P2, … , Pm, with m > 1. The Number of ways of choosing P1, P2, …, Pm so that P1 P2 … Pm= A is -

A is a set containing n elements. A subset P1 is chosen, and A is reconstructed by replacing the elements of P1. The same process is repeated for subsets P1, P2, … , Pm, with m > 1. The Number of ways of choosing P1, P2, …, Pm so that P1 P2 … Pm= A is -

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| k, |y| k, |x – y| k ; is-

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| k, |y| k, |x – y| k ; is-

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The cartesian equation of $r squared c o s space 2 theta equals a squared$ is

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations. Here we have to find the cartesian equation of $r squared c o s space 2 theta equals a squared$ .

The correct answer is: $x to the power of 2 end exponent minus y to the power of 2 end exponent equals a to the power of 2 end exponent$

The castesian equation of $r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p$ is

The castesian equation of $r c o s invisible function application left parenthesis theta minus alpha right parenthesis equals p$ is

The equation of the directrix of the conic $r C o s to the power of 2 end exponent invisible function application open parentheses fraction numerator theta over denominator 2 end fraction close parentheses equals 5$ is

The equation of the directrix of the conic $r C o s to the power of 2 end exponent invisible function application open parentheses fraction numerator theta over denominator 2 end fraction close parentheses equals 5$ is

(Area of $increment$ GPL) to (Area of $increment$ ALD) is equal to

(Area of $increment$ GPL) to (Area of $increment$ ALD) is equal to

Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is

The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is