Maths-
General
Easy

Question

The general solution of the trigonometric equation sin invisible function application x plus cos invisible function application x equals 1 is given by

  1. x equals 2 n pi comma blank n equals 0 comma blank plus-or-minus 1 comma blank plus-or-minus 2 comma horizontal ellipsis  
  2. x equals 2 n pi plus pi divided by 2 semicolon n equals 0 comma blank plus-or-minus comma blank plus-or-minus 2 comma horizontal ellipsis  
  3. x equals n pi plus open parentheses negative 1 close parentheses to the power of n end exponent fraction numerator pi over denominator 4 end fraction minus fraction numerator pi over denominator 4 end fraction blank n equals 0 comma blank plus-or-minus 1 comma blank plus-or-minus 2 comma horizontal ellipsis  
  4. None of these  

The correct answer is: x equals n pi plus open parentheses negative 1 close parentheses to the power of n end exponent fraction numerator pi over denominator 4 end fraction minus fraction numerator pi over denominator 4 end fraction blank n equals 0 comma blank plus-or-minus 1 comma blank plus-or-minus 2 comma horizontal ellipsis


    sin invisible function application x plus cos invisible function application x equals 1
    rightwards double arrow fraction numerator 1 over denominator square root of 2 end fraction sin invisible function application x plus fraction numerator 1 over denominator square root of 2 end fraction cos invisible function application x equals fraction numerator 1 over denominator square root of 2 end fraction
    rightwards double arrow sin invisible function application x cos invisible function application left parenthesis pi divided by 4 right parenthesis plus cos invisible function application x sin invisible function application left parenthesis pi divided by 4 right parenthesis equals sin invisible function application pi divided by 4
    rightwards double arrow sin invisible function application left parenthesis x plus pi divided by 4 right parenthesis equals sin invisible function application pi divided by 4
    rightwards double arrow x plus left parenthesis pi divided by 4 right parenthesis equals n pi plus open parentheses negative 1 close parentheses to the power of n end exponent blank pi divided by 4 comma blank n element of Z
    rightwards double arrow x equals n pi plus left square bracket open parentheses negative 1 close parentheses to the power of n end exponent blank pi divided by 4 right square bracket minus pi divided by 4
    Where n equals 0 comma blank plus-or-minus 1 comma blank plus-or-minus 2 comma horizontal ellipsis

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