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Physics-

General

Easy

Question

In a uniform magnetic field of induction $B$ , a wire in the form of semicircle of radius $blank r$ rotates about the diameter of the circle with angular frequency $blank omega$ . If the total resistance of the circuit is $R$ , the mean power generated per period of rotation is

$\frac{B π r^{2} ω}{2 R}$
$\frac{{(B π r^{2} ω)}^{2}}{5 R t}$
$\frac{{(B π r ω)}^{2}}{2 R}$
$\frac{{(B π r ω^{2})}^{2}}{8 R}$

The correct answer is: $fraction numerator open parentheses B pi r to the power of 2 end exponent omega close parentheses to the power of 2 end exponent over denominator 5 blank R t end fraction$

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