Maths-
General
Easy

Question

The locus of a point equidistant from two points A (stack a with rightwards arrow on top) & B (stack b with rightwards arrow on top) is-

  1. [stack r with rightwards arrow on top– (stack a with rightwards arrow on top+stack b with rightwards arrow on top) ]. stack b with rightwards arrow on top = 0  
  2. open parentheses stack r with rightwards arrow on top – fraction numerator stack a with rightwards arrow on top plus stack b with rightwards arrow on top over denominator 2 end fraction close parentheses. stack a with rightwards arrow on top= 0  
  3. open parentheses stack r with rightwards arrow on top – fraction numerator 1 over denominator 2 end fraction left parenthesis stack a with rightwards arrow on top plus stack b with rightwards arrow on top right parenthesis close parentheses. left parenthesis stack a with rightwards arrow on top minus stack b with rightwards arrow on top right parenthesis = 0  
  4. None of these  

The correct answer is: open parentheses stack r with rightwards arrow on top – fraction numerator 1 over denominator 2 end fraction left parenthesis stack a with rightwards arrow on top plus stack b with rightwards arrow on top right parenthesis close parentheses. left parenthesis stack a with rightwards arrow on top minus stack b with rightwards arrow on top right parenthesis = 0


    P(stack r with ̄ on top) lies on  bisector

    Error converting from MathML to accessible text.. Error converting from MathML to accessible text.= 0

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