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Maths-

General

Easy

Question

The minimum value of $27 t a n to the power of 2 end exponent invisible function application theta plus 3 c o t to the power of 2 end exponent invisible function application theta$ is

15
18
24
30

The correct answer is: 18

Related Questions to study

The maximum value of $open parentheses c o s invisible function application alpha subscript 1 end subscript close parentheses open parentheses c o s invisible function application alpha subscript 2 end subscript close parentheses$ $open parentheses c o s invisible function application alpha subscript n end subscript close parentheses$ , under the restrictions $0 less or equal than alpha subscript 1 end subscript comma alpha subscript 2 end subscript comma horizontal ellipsis. alpha subscript n end subscript less or equal than fraction numerator pi over denominator 2 end fraction$ and $open parentheses c o t invisible function application alpha subscript 1 end subscript close parentheses open parentheses c o t invisible function application alpha subscript 2 end subscript close parentheses horizontal ellipsis open parentheses c o t invisible function application alpha subscript n end subscript close parentheses equals 1$

The maximum value of $open parentheses c o s invisible function application alpha subscript 1 end subscript close parentheses open parentheses c o s invisible function application alpha subscript 2 end subscript close parentheses$ $open parentheses c o s invisible function application alpha subscript n end subscript close parentheses$ , under the restrictions $0 less or equal than alpha subscript 1 end subscript comma alpha subscript 2 end subscript comma horizontal ellipsis. alpha subscript n end subscript less or equal than fraction numerator pi over denominator 2 end fraction$ and $open parentheses c o t invisible function application alpha subscript 1 end subscript close parentheses open parentheses c o t invisible function application alpha subscript 2 end subscript close parentheses horizontal ellipsis open parentheses c o t invisible function application alpha subscript n end subscript close parentheses equals 1$

The maximum value of $s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is equal to

The maximum value of $s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is equal to

Range of $c o s to the power of 4 end exponent invisible function application x minus s i n to the power of 4 end exponent invisible function application x$ is

Range of $c o s to the power of 4 end exponent invisible function application x minus s i n to the power of 4 end exponent invisible function application x$ is

parallel

The maximum value of $16 c o s to the power of 5 end exponent invisible function application theta minus 20 c o s to the power of 3 end exponent invisible function application theta plus 5 c o s invisible function application theta$ is

The maximum value of $16 c o s to the power of 5 end exponent invisible function application theta minus 20 c o s to the power of 3 end exponent invisible function application theta plus 5 c o s invisible function application theta$ is

The range of $c o s invisible function application x plus 4 square root of 2 s i n invisible function application open parentheses x minus fraction numerator pi over denominator 4 end fraction close parentheses plus 6$ is

The range of $c o s invisible function application x plus 4 square root of 2 s i n invisible function application open parentheses x minus fraction numerator pi over denominator 4 end fraction close parentheses plus 6$ is

Period of $s i n invisible function application left parenthesis s i n invisible function application x right parenthesis plus s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is

Period of $s i n invisible function application left parenthesis s i n invisible function application x right parenthesis plus s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is

parallel

Period of $t a n invisible function application open parentheses x plus 8 x plus 27 x plus midline horizontal ellipsis plus n to the power of 3 end exponent x close parentheses$ is

Period of $t a n invisible function application open parentheses x plus 8 x plus 27 x plus midline horizontal ellipsis plus n to the power of 3 end exponent x close parentheses$ is

$A equals s i n to the power of 8 end exponent invisible function application theta plus c o s to the power of 14 end exponent invisible function application theta$ then for all values of $theta$

$A equals s i n to the power of 8 end exponent invisible function application theta plus c o s to the power of 14 end exponent invisible function application theta$ then for all values of $theta$

Period of $s i n invisible function application left parenthesis x plus 2 x plus 3 x plus midline horizontal ellipsis plus n x right parenthesis$ is

Period of $s i n invisible function application left parenthesis x plus 2 x plus 3 x plus midline horizontal ellipsis plus n x right parenthesis$ is

parallel

The function $f colon R rightwards arrow R g colon R rightwards arrow R$ are defined as follows $f left parenthesis x right parenthesis equals 0 left parenthesis x$ is rational $right parenthesis comma g left parenthesis x right parenthesis equals negative 1 left parenthesis x$ is rational $right parenthesis equals$ $1 left parenthesis x$ is irrational $equals 0$ ( $x$ is irrational $right parenthesis$ then fog $left parenthesis pi right parenthesis plus g o f invisible function application left parenthesis e right parenthesis$

The function $f colon R rightwards arrow R g colon R rightwards arrow R$ are defined as follows $f left parenthesis x right parenthesis equals 0 left parenthesis x$ is rational $right parenthesis comma g left parenthesis x right parenthesis equals negative 1 left parenthesis x$ is rational $right parenthesis equals$ $1 left parenthesis x$ is irrational $equals 0$ ( $x$ is irrational $right parenthesis$ then fog $left parenthesis pi right parenthesis plus g o f invisible function application left parenthesis e right parenthesis$

$f colon R rightwards arrow R$ and $g colon R rightwards arrow R$ are given by $f left parenthesis x right parenthesis equals vertical line x vertical line$ and $g left parenthesis x right parenthesis equals left square bracket x right square bracket$ for each $x element of R$ then $x element of R colon g left square bracket f left parenthesis x right parenthesis right square bracket less or equal than f left square bracket g left parenthesis x right parenthesis right square bracket$

$f colon R rightwards arrow R$ and $g colon R rightwards arrow R$ are given by $f left parenthesis x right parenthesis equals vertical line x vertical line$ and $g left parenthesis x right parenthesis equals left square bracket x right square bracket$ for each $x element of R$ then $x element of R colon g left square bracket f left parenthesis x right parenthesis right square bracket less or equal than f left square bracket g left parenthesis x right parenthesis right square bracket$

If $Q$ denotes the set of all rational numbers and $f open parentheses fraction numerator p over denominator q end fraction close parentheses equals square root of p to the power of 2 end exponent minus q to the power of 2 end exponent end root$ for any $fraction numerator p over denominator q end fraction element of$ Q, then observe the following statements
I) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is real for each $fraction numerator p over denominator q end fraction element of Q$
II) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is a complex number for each $fraction numerator p over denominator q end fraction element of Q$ Which of the following is correct?

If $Q$ denotes the set of all rational numbers and $f open parentheses fraction numerator p over denominator q end fraction close parentheses equals square root of p to the power of 2 end exponent minus q to the power of 2 end exponent end root$ for any $fraction numerator p over denominator q end fraction element of$ Q, then observe the following statements
I) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is real for each $fraction numerator p over denominator q end fraction element of Q$
II) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is a complex number for each $fraction numerator p over denominator q end fraction element of Q$ Which of the following is correct?

parallel

If $Z rightwards arrow Z$ is defined byf $left parenthesis x right parenthesis equals open curly brackets table row cell fraction numerator x over denominator 2 end fraction text if end text x text is even end text end cell row cell 0 text if end text x text odd end text end cell end table close$ then $f$ is

If $Z rightwards arrow Z$ is defined byf $left parenthesis x right parenthesis equals open curly brackets table row cell fraction numerator x over denominator 2 end fraction text if end text x text is even end text end cell row cell 0 text if end text x text odd end text end cell end table close$ then $f$ is

Let $f to the power of ´ end exponent$ be an injective function with domain $left curly bracket x comma y comma z right curly bracket$ and range $left curly bracket 1 , 2 comma 3 right curly bracket$ such that exactly one of the following statements is correct and the remaining are flase $f left parenthesis x right parenthesis equals 1$ , $f left parenthesis y right parenthesis not equal to$ $1 comma f left parenthesis z right parenthesis not equal to 2$ the value of $f to the power of negative 1 end exponent$ (1) is

Let $f to the power of ´ end exponent$ be an injective function with domain $left curly bracket x comma y comma z right curly bracket$ and range $left curly bracket 1 , 2 comma 3 right curly bracket$ such that exactly one of the following statements is correct and the remaining are flase $f left parenthesis x right parenthesis equals 1$ , $f left parenthesis y right parenthesis not equal to$ $1 comma f left parenthesis z right parenthesis not equal to 2$ the value of $f to the power of negative 1 end exponent$ (1) is

The domain of the function $f left parenthesis x right parenthesis equals root index 3 of fraction numerator 2 x minus 1 over denominator x to the power of 2 end exponent minus 10 x minus 11 end fraction end root$

The domain of the function $f left parenthesis x right parenthesis equals root index 3 of fraction numerator 2 x minus 1 over denominator x to the power of 2 end exponent minus 10 x minus 11 end fraction end root$

parallel

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