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Maths-

General

Easy

Question

The range of $c o s invisible function application x plus 4 square root of 2 s i n invisible function application open parentheses x minus fraction numerator pi over denominator 4 end fraction close parentheses plus 6$ is

$[1,11]$
$[- 1,11]$
$[2,10]$
$[10,11]$

The correct answer is: $open square brackets 111 close square brackets$

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Period of $s i n invisible function application left parenthesis s i n invisible function application x right parenthesis plus s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is

Period of $s i n invisible function application left parenthesis s i n invisible function application x right parenthesis plus s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is

Period of $t a n invisible function application open parentheses x plus 8 x plus 27 x plus midline horizontal ellipsis plus n to the power of 3 end exponent x close parentheses$ is

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$A equals s i n to the power of 8 end exponent invisible function application theta plus c o s to the power of 14 end exponent invisible function application theta$ then for all values of $theta$

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parallel

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