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Maths-

General

Easy

Question

Period of $s i n invisible function application left parenthesis s i n invisible function application x right parenthesis plus s i n invisible function application left parenthesis c o s invisible function application x right parenthesis$ is

$π$
$2 π$
$\frac{π}{2}$
$\frac{π}{4}$

The correct answer is: $2 pi$

Related Questions to study

Period of $t a n invisible function application open parentheses x plus 8 x plus 27 x plus midline horizontal ellipsis plus n to the power of 3 end exponent x close parentheses$ is

Period of $t a n invisible function application open parentheses x plus 8 x plus 27 x plus midline horizontal ellipsis plus n to the power of 3 end exponent x close parentheses$ is

$A equals s i n to the power of 8 end exponent invisible function application theta plus c o s to the power of 14 end exponent invisible function application theta$ then for all values of $theta$

$A equals s i n to the power of 8 end exponent invisible function application theta plus c o s to the power of 14 end exponent invisible function application theta$ then for all values of $theta$

Period of $s i n invisible function application left parenthesis x plus 2 x plus 3 x plus midline horizontal ellipsis plus n x right parenthesis$ is

Period of $s i n invisible function application left parenthesis x plus 2 x plus 3 x plus midline horizontal ellipsis plus n x right parenthesis$ is

parallel

The function $f colon R rightwards arrow R g colon R rightwards arrow R$ are defined as follows $f left parenthesis x right parenthesis equals 0 left parenthesis x$ is rational $right parenthesis comma g left parenthesis x right parenthesis equals negative 1 left parenthesis x$ is rational $right parenthesis equals$ $1 left parenthesis x$ is irrational $equals 0$ ( $x$ is irrational $right parenthesis$ then fog $left parenthesis pi right parenthesis plus g o f invisible function application left parenthesis e right parenthesis$

The function $f colon R rightwards arrow R g colon R rightwards arrow R$ are defined as follows $f left parenthesis x right parenthesis equals 0 left parenthesis x$ is rational $right parenthesis comma g left parenthesis x right parenthesis equals negative 1 left parenthesis x$ is rational $right parenthesis equals$ $1 left parenthesis x$ is irrational $equals 0$ ( $x$ is irrational $right parenthesis$ then fog $left parenthesis pi right parenthesis plus g o f invisible function application left parenthesis e right parenthesis$

$f colon R rightwards arrow R$ and $g colon R rightwards arrow R$ are given by $f left parenthesis x right parenthesis equals vertical line x vertical line$ and $g left parenthesis x right parenthesis equals left square bracket x right square bracket$ for each $x element of R$ then $x element of R colon g left square bracket f left parenthesis x right parenthesis right square bracket less or equal than f left square bracket g left parenthesis x right parenthesis right square bracket$

$f colon R rightwards arrow R$ and $g colon R rightwards arrow R$ are given by $f left parenthesis x right parenthesis equals vertical line x vertical line$ and $g left parenthesis x right parenthesis equals left square bracket x right square bracket$ for each $x element of R$ then $x element of R colon g left square bracket f left parenthesis x right parenthesis right square bracket less or equal than f left square bracket g left parenthesis x right parenthesis right square bracket$

If $Q$ denotes the set of all rational numbers and $f open parentheses fraction numerator p over denominator q end fraction close parentheses equals square root of p to the power of 2 end exponent minus q to the power of 2 end exponent end root$ for any $fraction numerator p over denominator q end fraction element of$ Q, then observe the following statements
I) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is real for each $fraction numerator p over denominator q end fraction element of Q$
II) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is a complex number for each $fraction numerator p over denominator q end fraction element of Q$ Which of the following is correct?

If $Q$ denotes the set of all rational numbers and $f open parentheses fraction numerator p over denominator q end fraction close parentheses equals square root of p to the power of 2 end exponent minus q to the power of 2 end exponent end root$ for any $fraction numerator p over denominator q end fraction element of$ Q, then observe the following statements
I) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is real for each $fraction numerator p over denominator q end fraction element of Q$
II) $f open parentheses fraction numerator p over denominator q end fraction close parentheses$ is a complex number for each $fraction numerator p over denominator q end fraction element of Q$ Which of the following is correct?

parallel

If $Z rightwards arrow Z$ is defined byf $left parenthesis x right parenthesis equals open curly brackets table row cell fraction numerator x over denominator 2 end fraction text if end text x text is even end text end cell row cell 0 text if end text x text odd end text end cell end table close$ then $f$ is

If $Z rightwards arrow Z$ is defined byf $left parenthesis x right parenthesis equals open curly brackets table row cell fraction numerator x over denominator 2 end fraction text if end text x text is even end text end cell row cell 0 text if end text x text odd end text end cell end table close$ then $f$ is

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The domain of the function $f left parenthesis x right parenthesis equals root index 3 of fraction numerator 2 x minus 1 over denominator x to the power of 2 end exponent minus 10 x minus 11 end fraction end root$

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parallel

If $f left parenthesis x right parenthesis equals l o g invisible function application open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses$ then $f open parentheses x subscript 1 end subscript close parentheses plus f open parentheses x subscript 2 end subscript close parentheses equals$

If $f left parenthesis x right parenthesis equals l o g invisible function application open parentheses fraction numerator 1 plus x over denominator 1 minus x end fraction close parentheses$ then $f open parentheses x subscript 1 end subscript close parentheses plus f open parentheses x subscript 2 end subscript close parentheses equals$

For a $d$ electron, the orbital angular momentum is

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Which one of the following sets of quantum number represents an impossible arrangement?

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Chemistry-General

parallel

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