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Maths-

General

Easy

Question

The number of ways to fill each of the four cells of the table with a distinct natural number such that the sum of the numbers is 10 and the sums of the numbers placed diagonally are equal, is-

2! × 2!
4!
2(4!)
None of these

The correct answer is: None of these

Related Questions to study

Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain n people, where n is-

Two teams are to play a series of 5 matches between them. A match ends in a win or loss or draw for a team. A number of people forecast the result of each match and no two people make the same forecast for the series of matches. The smallest group of people in which one person forecasts correctly for all the matches will contain n people, where n is-

The number of ways in which, 2n things of one sort, 2n things of another sort and 2n of a third sort can be divided between two person so that each get 3n things is -

The number of ways in which, 2n things of one sort, 2n things of another sort and 2n of a third sort can be divided between two person so that each get 3n things is -

The current passing through a choke coil of 5 henry is decreasing at the rate of $2 blank a m p e r e divided by s e c$ . The e.m.f. developing across the coil is

The current passing through a choke coil of 5 henry is decreasing at the rate of $2 blank a m p e r e divided by s e c$ . The e.m.f. developing across the coil is

Physics-General

parallel

The energy stored in an inductor of self inductance $L$ henry carrying a current of 1 A is

The energy stored in an inductor of self inductance $L$ henry carrying a current of 1 A is

Physics-General

If $tan invisible function application open parentheses A minus B close parentheses equals 1$ and $sec invisible function application open parentheses A plus B close parentheses equals 2 divided by square root of 3 comma blank$ then the smallest positive values of $A blank$ and $B comma$ respectively, are

If $tan invisible function application open parentheses A minus B close parentheses equals 1$ and $sec invisible function application open parentheses A plus B close parentheses equals 2 divided by square root of 3 comma blank$ then the smallest positive values of $A blank$ and $B comma$ respectively, are

Let $n$ be a positive integer such that $sin invisible function application fraction numerator pi over denominator 2 n end fraction plus cos invisible function application fraction numerator pi over denominator 2 n end fraction equals fraction numerator square root of x over denominator 2 end fraction.$ Then

Let $n$ be a positive integer such that $sin invisible function application fraction numerator pi over denominator 2 n end fraction plus cos invisible function application fraction numerator pi over denominator 2 n end fraction equals fraction numerator square root of x over denominator 2 end fraction.$ Then

parallel

In triangle $A B C comma$ if $sin invisible function application A cos invisible function application B equals fraction numerator 1 over denominator 4 end fraction$ and $blank 3 tan invisible function application A equals tan invisible function application B$ , then $cot to the power of 2 end exponent invisible function application A$ is equal to

In triangle $A B C comma$ if $sin invisible function application A cos invisible function application B equals fraction numerator 1 over denominator 4 end fraction$ and $blank 3 tan invisible function application A equals tan invisible function application B$ , then $cot to the power of 2 end exponent invisible function application A$ is equal to

If $y equals open parentheses 1 plus tan invisible function application A close parentheses open parentheses 1 minus tan invisible function application B close parentheses blank$ where $blank A minus B equals fraction numerator pi over denominator 4 end fraction comma$ then $open parentheses y plus 1 close parentheses to the power of y plus 1 end exponent blank$ is equal to

If $y equals open parentheses 1 plus tan invisible function application A close parentheses open parentheses 1 minus tan invisible function application B close parentheses blank$ where $blank A minus B equals fraction numerator pi over denominator 4 end fraction comma$ then $open parentheses y plus 1 close parentheses to the power of y plus 1 end exponent blank$ is equal to

The number of solutions of $sin invisible function application x plus sin invisible function application 2 x plus sin invisible function application 3 x equals cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x comma blank 0 less or equal than x less or equal than 2 pi comma$ is

The number of solutions of $sin invisible function application x plus sin invisible function application 2 x plus sin invisible function application 3 x equals cos invisible function application x plus cos invisible function application 2 x plus cos invisible function application 3 x comma blank 0 less or equal than x less or equal than 2 pi comma$ is

parallel

In a set of teachers of a school, two teachers are said to be related if they “teach the same subject”, then the relation is

In a set of teachers of a school, two teachers are said to be related if they “teach the same subject”, then the relation is

If $A equals open curly brackets 13 comma 57 comma 911131517 close curly brackets comma B equals left curly bracket 24 horizontal ellipsis comma 18 right curly bracket$ and $N$ is the universal set, then $A ´ union left parenthesis left parenthesis A union B right parenthesis intersection B ´ right parenthesis$ is

If $A equals open curly brackets 13 comma 57 comma 911131517 close curly brackets comma B equals left curly bracket 24 horizontal ellipsis comma 18 right curly bracket$ and $N$ is the universal set, then $A ´ union left parenthesis left parenthesis A union B right parenthesis intersection B ´ right parenthesis$ is

In the set $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma$ a relation $R$ is defined by $R equals open curly brackets open parentheses x comma y close parentheses colon x comma y element of A blank a n d blank x less than y close curly brackets.$ Then, $R$ is

In the set $A equals open curly brackets 1 comma blank 2 comma blank 3 comma blank 4 comma blank 5 close curly brackets comma$ a relation $R$ is defined by $R equals open curly brackets open parentheses x comma y close parentheses colon x comma y element of A blank a n d blank x less than y close curly brackets.$ Then, $R$ is

parallel

Consider the set $A$ of all determinants of order 3 with entries 0 or 1 only. Let $B$ be the subset of $A$ consisting of all determinants with value 1. Let C be the subset of the set of all determinants with value $negative 1.$ Then

Consider the set $A$ of all determinants of order 3 with entries 0 or 1 only. Let $B$ be the subset of $A$ consisting of all determinants with value 1. Let C be the subset of the set of all determinants with value $negative 1.$ Then

Suppose $A subscript 1 end subscript comma blank A subscript 2 end subscript comma horizontal ellipsis comma A subscript 30 end subscript$ are thirty sets, each having 5 elements and $B subscript 1 end subscript comma blank B subscript 2 end subscript comma blank horizontal ellipsis comma blank B subscript n end subscript$ are $n$ sets each with 3 elements, let
$not stretchy ⋃ subscript i equals 1 end subscript superscript 30 end superscript A subscript i end subscript equals not stretchy ⋃ subscript j equals 1 end subscript superscript n end superscript B subscript j end subscript equals S$ and each element of $S$ belongs to exactly 10 of the $A subscript i end subscript$ 's and exactly 9 of the $B subscript j end subscript$ 's. Then, $n$ is equal to

Suppose $A subscript 1 end subscript comma blank A subscript 2 end subscript comma horizontal ellipsis comma A subscript 30 end subscript$ are thirty sets, each having 5 elements and $B subscript 1 end subscript comma blank B subscript 2 end subscript comma blank horizontal ellipsis comma blank B subscript n end subscript$ are $n$ sets each with 3 elements, let
$not stretchy ⋃ subscript i equals 1 end subscript superscript 30 end superscript A subscript i end subscript equals not stretchy ⋃ subscript j equals 1 end subscript superscript n end superscript B subscript j end subscript equals S$ and each element of $S$ belongs to exactly 10 of the $A subscript i end subscript$ 's and exactly 9 of the $B subscript j end subscript$ 's. Then, $n$ is equal to

Three sets $A comma blank B comma blank C$ are such that $A equals B intersection C$ and $B equals C intersection A$ , then

Three sets $A comma blank B comma blank C$ are such that $A equals B intersection C$ and $B equals C intersection A$ , then

parallel

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