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Question

The slope of the tangent to the curves x equals t to the power of 2 end exponent plus 3 t minus 8 comma blank y equals 2 t to the power of 2 end exponent minus 2 t minus 5 at the point (2 comma blank minus 1 right parenthesis blankis

  1. 22/7  
  2. 6/7  
  3. -6  
  4. -7  

The correct answer is: 6/7


    Given curve are
    x equals t to the power of 2 end exponent minus 3 t minus 8 comma blank y equals 2 t to the power of 2 end exponent minus 2 t minus 5 …(i)

    When x equals 2, then

    2 equals t to the power of 2 end exponent plus 3 t minus 8

    rightwards double arrow blank t to the power of 2 end exponent plus 3 t minus 10 equals 0 blank rightwards double arrow blank t equals 2 comma blank minus 5 ...(ii)

    When y equals negative 1, then

    negative 1 equals 2 t to the power of 2 end exponent minus 2 t minus 5

    rightwards double arrow blank 2 t to the power of 2 end exponent minus 2 t minus 4 equals 0 blank rightwards double arrow blank t equals negative 1 comma blank 2 ...(iii)

    From Eqs. (ii) and (iii), t equals 2

    On differentiating Eq. (i) w.r.t. t respectively, we get

    fraction numerator d x over denominator d t end fraction equals 2 t plus 3 and fraction numerator d y over denominator d t end fraction equals 4 t minus 2

    therefore blank fraction numerator d y over denominator d x end fraction equals fraction numerator d y divided by d t over denominator d x divided by d t end fraction equals fraction numerator 4 t minus 2 over denominator 2 t plus 3 end fraction

    rightwards double arrow blank open parentheses fraction numerator d y over denominator d x end fraction close parentheses subscript left parenthesis t equals 2 right parenthesis end subscript equals fraction numerator 8 minus 2 over denominator 4 plus 3 end fraction equals fraction numerator 6 over denominator 7 end fraction

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