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The vectors 2 stack i with rightwards arrow on top plus 3 stack j with rightwards arrow on top comma 5 stack i with rightwards arrow on top plus 6 stack j with rightwards arrow on top   and 8 stack i with rightwards arrow on top plus lambda stack j with rightwards arrow on top have their initial points at (1, 1). The value of lambda so that the vectors terminate on one straight line is

  1. 0    
  2. 3    
  3. 6    
  4. 9.    

The correct answer is: 9.


    Since the vectors 2 stack i with rightwards arrow on top plus 3 stack j with rightwards arrow on top text and end text 5 stack i with rightwards arrow on top plus 6 stack j with rightwards arrow on top have (1, 1) as initial point. \ their terminal points are (3, 4) and (6, 7) respectively. The equation of the line joining these two points is
    y minus 4 equals fraction numerator 7 minus 4 over denominator 6 minus 3 end fraction left parenthesis x minus 3 right parenthesis i. e. x minus y plus 1 equals 0 text Theterminalpointof end text 8 stack i with rightwards arrow on top plus lambda stack j with rightwards arrow on top i s left parenthesis 9 comma lambda plus 1 right parenthesis.
    Since the vectors terminate on the same st. line \ (9, lambda +1) lies on x minus y plus 1 equals 0 and \ 9 – (l -1) + 1 = 0 Þ l = 9.

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