Maths-
General
Easy
Question
Three distinct numbers are selected from first 100 natural numbers. The probability that all the three numbers are divisible by 2 and 3 is
- 4/25
- 4/35
- 4/55
- 4/1155
Hint:
The given question is of probability. Probability gives information about an occurance of event. We are given 100 natural numbers. We have to find the numbers that are divisible by both 2 and 3.
The correct answer is: 4/1155
Probability = 
Total number of outcome means choosing 3 numbers from 100 natural number. The way of choosing 3 numbers from 100 numbers without repeating is given by 
Favorable outcome means number that are divisible by both 3 and 2.
The numbers that are divisible by both 2 and 3 must be divisible by 2 × 3 = 6.
The number of digits that at are divisible by 6 from 1 to 100 is 16.
We have to choose 3 number from the 16 numbers is 
.
We know that 
Probability = 
= 
This is the required answer.
We should know the formula for combinations. We should know the concept of probability.
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The product of the following reaction is:
<img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/649779/1/1178377/Picture21.png" alt="" width="285" height="89"
Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the. addition ·of hydrogen takes·· place in presence of Raney nickel· catalyst. Platinum and palladium can also be used as catalyst in these reactions. These are heterogeneous catalyst and used in. finely. divided state. Experimentally, it is observed that less. crowded alkenes adsorb H2 with faster rate. Controlled hydrogeneration of alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order:
Non-terminal alkynes an reduce4 in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product. .
The product of the following reaction is:
<img src="https://mycourses.turito.com/tokenpluginfile.php/c161933dbfaab094c54655ab71e9b8f0/1/question/questiontext/649779/1/1178377/Picture21.png" alt="" width="285" height="89"
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Non-terminal alkynes an reduce4 in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product.
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Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the. addition ·of hydrogen takes·· place in presence of Raney nickel· catalyst. Platinum and palladium can also be used as catalyst in these reactions. These are heterogeneous catalyst and used in. finely. divided state. Experimentally, it is observed that less. crowded alkenes adsorb H2 with faster rate. Controlled hydrogeneration of alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order:
Non-terminal alkynes an reduce4 in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product.
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Non-terminal alkynes a reduce4 in presence of Na or Li metal dissolved in liquid ammonia. In this reaction, anti-addition of hydrogen results into the trans-product.
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</span
Hydrogenation of alkenes and alkynes takes place in presence of certain catalysts. In Sabatier Senderen's reaction, the. addition ·of hydrogen takes·· place in presence of Raney nickel· catalyst. Platinum and palladium can also be used as catalyst in these reactions. These are heterogeneous catalyst and used in. finely. divided state. Experimentally, it is observed that less. crowded alkenes adsorb H2 with faster rate. Controlled hydrogeneration of alkyne in presence of Lindlar's catalyst yields cis product i.e., 'cis' alkene. Thus, in presence of Lindlar's catalyst 'syn' addition takes place. The relative rate of hydrogenation follows the order:
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I)
II)
III)
IV) </span
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