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Question

ven A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application theta comma then for all real theta,

  1. 1 less or equal than A less or equal than 2  
  2. 3 divided by 4 less or equal than A less or equal than 1  
  3. 13 divided by 16 less or equal than A less or equal than 1  
  4. 3 divided by 4 less or equal than A less or equal than 13 divided by 16  

The correct answer is: 3 divided by 4 less or equal than A less or equal than 1


    We have sin to the power of 2 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application cos to the power of 2 end exponent invisible function application theta less or equal than sin to the power of 2 end exponent invisible function application theta plus cos to the power of 2 end exponent invisible function application blank theta left square bracket because cos to the power of 2 end exponent invisible function application theta less or equal than 1 right square bracket
    Again, A equals sin to the power of 2 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta equals 1 minus cos to the power of 2 end exponent invisible function application theta plus cos to the power of 4 end exponent invisible function application theta equals 1 plus left parenthesis cos to the power of 4 end exponent invisible function application theta minus cos to the power of 2 end exponent invisible function application theta right parenthesis
    equals 1 plus open parentheses cos to the power of 2 end exponent invisible function application theta minus fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 2 end exponent minus fraction numerator 1 over denominator 4 end fraction equals fraction numerator 3 over denominator 4 end fraction plus open parentheses cos to the power of 2 end exponent invisible function application theta minus fraction numerator 1 over denominator 2 end fraction close parentheses to the power of 2 end exponent greater or equal than fraction numerator 3 over denominator 4 end fraction
    Hence, 3 divided by 4 less or equal than A less or equal than 1

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