Which of the following is a perfect number?

$c o s invisible function application e c to the power of 2 end exponent 60 to the power of ring operator end exponent s e c to the power of 2 end exponent invisible function application 30 to the power of ring operator end exponent c o s invisible function application 0 to the power of ring operator end exponent s i n invisible function application 45 to the power of ring operator end exponent c o t to the power of 2 end exponent invisible function application 60 to the power of ring operator end exponent t a n to the power of 2 end exponent invisible function application 60 to the power of ring operator end exponent equals$

$4 open parentheses s i n to the power of 4 end exponent invisible function application 30 to the power of ring operator end exponent plus c o s to the power of 4 end exponent invisible function application 60 to the power of ring operator end exponent close parentheses plus fraction numerator 2 over denominator 3 end fraction open parentheses s i n to the power of 2 end exponent invisible function application 60 to the power of ring operator end exponent minus c o s to the power of 2 end exponent invisible function application 45 to the power of ring operator end exponent close parentheses plus fraction numerator 1 over denominator 2 end fraction t a n to the power of 2 end exponent invisible function application 60 to the power of ring operator end exponent equals$

cot $theta$ + tan $theta$ =

Hence option 2 is correct

cot $theta$ + tan $theta$ =

Hence option 2 is correct

$open parentheses 1 plus c o t to the power of 2 end exponent invisible function application theta close parentheses left parenthesis 1 minus c o s invisible function application theta right parenthesis left parenthesis 1 plus c o s invisible function application theta right parenthesis equals$

Hence option 2 is correct

$open parentheses 1 plus c o t to the power of 2 end exponent invisible function application theta close parentheses left parenthesis 1 minus c o s invisible function application theta right parenthesis left parenthesis 1 plus c o s invisible function application theta right parenthesis equals$

Hence option 2 is correct

If $s i n invisible function application A equals fraction numerator 1 over denominator 3 end fraction$ , then cos A cosecA + tan A sec A =

If sin B = 1/2 then 3cos B – 4 cos³ B =

Hence option 4 is correct

If sin B = 1/2 then 3cos B – 4 cos³ B =

Hence option 4 is correct

A minutes hand of a table clock is 3cm long. How far does its tip move in 20 minutes

If $fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus z to the power of 2 end exponent minus 64 over denominator x y minus y z minus z x end fraction equals negative 2 blank a n d blank x plus y equals 3 z comma blank t h e n blank t h e blank v a l u e blank o f blank z blank i s$

Hence option 3 is correct

If $fraction numerator x to the power of 2 end exponent plus y to the power of 2 end exponent plus z to the power of 2 end exponent minus 64 over denominator x y minus y z minus z x end fraction equals negative 2 blank a n d blank x plus y equals 3 z comma blank t h e n blank t h e blank v a l u e blank o f blank z blank i s$

Hence option 3 is correct

If $a to the power of 2 end exponent plus b to the power of 2 end exponent equals 117 blank a n d blank a b equals 54 comma blank t h e n blank fraction numerator a plus b over denominator a minus b end fraction blank i s$

Hence option 2 is correct

If $a to the power of 2 end exponent plus b to the power of 2 end exponent equals 117 blank a n d blank a b equals 54 comma blank t h e n blank fraction numerator a plus b over denominator a minus b end fraction blank i s$

Hence option 2 is correct

The appropriate formula that can be used to find the value of $open parentheses 50 fraction numerator 1 over denominator 4 end fraction cross times 49 fraction numerator 3 over denominator 4 end fraction close parentheses$

Hence option 3 is correct

The appropriate formula that can be used to find the value of $open parentheses 50 fraction numerator 1 over denominator 4 end fraction cross times 49 fraction numerator 3 over denominator 4 end fraction close parentheses$

Hence option 3 is correct

Divide $a x to the power of 2 end exponent minus a y to the power of 2 end exponent blank b y blank a x plus a y$

Hence option 1 is correct

Divide $a x to the power of 2 end exponent minus a y to the power of 2 end exponent blank b y blank a x plus a y$

Hence option 1 is correct

Find the missing term in $open parentheses fraction numerator 3 x over denominator 4 end fraction minus fraction numerator 4 y over denominator 3 end fraction close parentheses to the power of 2 end exponent equals fraction numerator 9 x to the power of 2 end exponent over denominator 16 end fraction plus horizontal ellipsis.. plus fraction numerator 16 y to the power of 2 end exponent over denominator 9 end fraction$

Hence option 2 is correct

Find the missing term in $open parentheses fraction numerator 3 x over denominator 4 end fraction minus fraction numerator 4 y over denominator 3 end fraction close parentheses to the power of 2 end exponent equals fraction numerator 9 x to the power of 2 end exponent over denominator 16 end fraction plus horizontal ellipsis.. plus fraction numerator 16 y to the power of 2 end exponent over denominator 9 end fraction$

Hence option 2 is correct

Find the probability of getting a number less than 5 in a single throw of a die

Hence option 2 is correct

Find the probability of getting a number less than 5 in a single throw of a die

Hence option 2 is correct

In the spinner shown, pointer can land on any of three parts of the same size. So there are three outcomes. What part of the whole is coloured?

So here we used the concept of fractions to understand the question. The numerical numbers that make up a fraction of the whole are called fractions. A whole can be a single item or a collection of items. When anything or a number is divided into equal parts, each piece represents a portion of the total. So the fraction in this question is 1/3.

In the spinner shown, pointer can land on any of three parts of the same size. So there are three outcomes. What part of the whole is coloured?