Question
Find the probability of getting a number less than 5 in a single throw of a die
The correct answer is:
To find the probability of finding a number less than 5
Numbers less than 5 are {1,2,3,4}
Die ={1,2,3,4,5,6}
Hence probability is 4/6=2/3
Hence option 2 is correct
Related Questions to study
In the spinner shown, pointer can land on any of three parts of the same size. So there are three outcomes. What part of the whole is coloured?
So here we used the concept of fractions to understand the question. The numerical numbers that make up a fraction of the whole are called fractions. A whole can be a single item or a collection of items. When anything or a number is divided into equal parts, each piece represents a portion of the total. So the fraction in this question is 1/3.
In the spinner shown, pointer can land on any of three parts of the same size. So there are three outcomes. What part of the whole is coloured?
So here we used the concept of fractions to understand the question. The numerical numbers that make up a fraction of the whole are called fractions. A whole can be a single item or a collection of items. When anything or a number is divided into equal parts, each piece represents a portion of the total. So the fraction in this question is 1/3.
A box contains 4 packs of chocolates. Anusha picks out a pack at random. What is the probability that she picks
A) Perk?
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Here we used the concept of probability to find the answer using events. A set of results from an experiment might be referred to as a probability event. In other words, a probability definition of an event is the subset of the relevant sample space. So the probabilities are 
.
A box contains 4 packs of chocolates. Anusha picks out a pack at random. What is the probability that she picks
A) Perk?
B) Kitkat?
Here we used the concept of probability to find the answer using events. A set of results from an experiment might be referred to as a probability event. In other words, a probability definition of an event is the subset of the relevant sample space. So the probabilities are .
In which class interval of wages there are less number of workers?
Hence option 4 is correct
In which class interval of wages there are less number of workers?
Hence option 4 is correct
What is the size of the class?
Hence option 1 is correct
What is the size of the class?
Hence option 1 is correct
What is the lowest value of rainfall?
Hence option 3 is corrrect
What is the lowest value of rainfall?
Hence option 3 is corrrect
In a Parallelogram the diagonals intersect at O. If 
then AC is
Hence option 4 is correct
In a Parallelogram the diagonals intersect at O. If then AC is
Hence option 4 is correct
ABCD is a Parallelogram. If 
ABCD is a Parallelogram. If
ABCD is a Quadrilateral in which 
ABCD is a Quadrilateral in which
PQRS is a Quadrilateral in which 
PQRS is a Quadrilateral in which
PQRS is a Quadrilateral in which 
So here we used the concept of a quadrilateral to understand the question. It is basically 4 sided shape that can take any figure. We also used the angle sum property of a quadrilateral which is 360 degrees. So here the angle R + S is 180 degrees.
PQRS is a Quadrilateral in which
So here we used the concept of a quadrilateral to understand the question. It is basically 4 sided shape that can take any figure. We also used the angle sum property of a quadrilateral which is 360 degrees. So here the angle R + S is 180 degrees.
ABCD is a Quadrilateral in which 
ABCD is a Quadrilateral in which
The diagonals of a Rectangle ABCD meet at O. If 
Hence option 2 is correct
The diagonals of a Rectangle ABCD meet at O. If
Hence option 2 is correct
A Square of side 4 units is combined with two right angled triangles of bases each 3units to form a Trapezium (as shown in figure). Then perimeter of the Trapezium is
Therefore, the perimeter of trapezium is 24 units.
A Square of side 4 units is combined with two right angled triangles of bases each 3units to form a Trapezium (as shown in figure). Then perimeter of the Trapezium is
Therefore, the perimeter of trapezium is 24 units.
In the figure, ABCD is a kite with AB = AD, BC = CD and 
O. If 
then a – b + c – d + e – f =
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Area of square field is 
. The length of each side is
Hence option 3 is correct
Area of square field is . The length of each side is
Hence option 3 is correct
