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Physics-

General

Easy

Question

4 eV is the energy of the incident photon and the work function in $2 e V.$ What is the stopping potential

2V
4V
6V
$2 \sqrt{2} V$

The correct answer is: 2V

$E equals W subscript 0 end subscript plus e V subscript 0 end subscript rightwards double arrow 4 e V equals 2 e V plus e V subscript 0 end subscript rightwards double arrow V subscript 0 end subscript equals 2 v o l t$

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