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Physics-

General

Easy

Question

A battery of emf 10 V and internal resistance $3 capital omega$ is connected to a resistor as shown in the figure. If the current in the circuit is 0.5 A. then the resistance of the resistor will be

19 $Ω$
17 $Ω$
10 $Ω$
12 $Ω$

The correct answer is: 17 $capital omega$

$i equals fraction numerator E over denominator R plus r end fraction rightwards double arrow 0.5 equals fraction numerator 10 over denominator R plus 3 end fraction$ Þ 10 = 0.5R + 1.5 Þ R = 17W.

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