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Physics-

General

Easy

Question

A capacitor of capacity $C subscript 1 end subscript$ is charged to the potential of $V subscript o end subscript$ . On disconnecting with the battery, it is connected with a capacitor of capacity $C subscript 2 end subscript$ as shown in the adjoining figure. The ratio of energies before and after the connection of switch $S$ will be

$(C_{1} + C_{2}) / C_{1}$
$C_{1} / (C_{1} + C_{2})$
$C_{1} C_{2}$
$C_{1} / C_{2}$

The correct answer is: $left parenthesis C subscript 1 end subscript plus C subscript 2 end subscript right parenthesis divided by C subscript 1 end subscript$

Energy (U) $equals fraction numerator q to the power of 2 end exponent over denominator 2 C end fraction$ . q remains same so $U proportional to fraction numerator 1 over denominator C end fraction$
Þ $fraction numerator C subscript 1 end subscript plus C subscript 2 end subscript over denominator C subscript 1 end subscript end fraction$

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