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Physics-

General

Easy

Question

A chain of 125 links is 1.25 m long and has mass of 2 kg with the ends fastened together. It is set for rotating at 50 $r e v s to the power of negative 1 end exponent$ , centripetal force on each links is

3.14 N
0.314 N
314 N
None of these

The correct answer is: 314 N

$F equals m r omega to the power of 2 end exponent$
$equals fraction numerator 2 over denominator 125 end fraction cross times fraction numerator 1.25 over denominator 2 pi end fraction cross times open parentheses 100 pi close parentheses to the power of 2 end exponent blank left parenthesis therefore omega equals 2 pi f equals 2 cross times 50 cross times pi right parenthesis$
$equals 100 pi N equals 314 N$

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