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Physics-

General

Easy

Question

In hydrogen atom, the electron is moving round the nucleus with velocity 2.18 $cross times 10 to the power of 6 end exponent m s to the power of negative 1 end exponent$ in an orbit of radius $0.528 blank Å$ . The acceleration of the electron is

9 $\times 10^{18} m s^{- 2}$
9 $\times 10^{22} m s^{- 2}$
9 $\times 10^{- 22} m s^{- 2}$
9 $\times 10^{12} m s^{- 2}$

The correct answer is: 9 $cross times 10 to the power of 22 end exponent blank m s to the power of negative 2 end exponent$

Acceleration of electron
$equals fraction numerator v to the power of 2 end exponent over denominator r end fraction equals fraction numerator open parentheses 2.18 cross times 10 to the power of 6 end exponent close parentheses to the power of 2 end exponent over denominator 0.528 cross times 10 to the power of negative 10 end exponent end fraction equals 9 cross times 10 to the power of 22 end exponent blank m s to the power of negative 2 end exponent$

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