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Physics-

General

Easy

Question

A coil of $40 blank capital omega$ resistance has 100 turns and radius $6 blank m m$ is connected to ammeter of resistance of $160 blank o h m s$ . Coil is placed perpendicular to the magnetic field. When coil is taken out of the field, $32 blank mu$ C charge flows through it. The intensity of magnetic field will be

$6.55 T$
$5.66 T$
$0.655 T$
$0.566 T$

The correct answer is: $0.566 blank T$

$q equals negative fraction numerator N over denominator R end fraction open parentheses B subscript 2 end subscript minus B subscript 1 end subscript close parentheses A cos invisible function application theta$
$32 cross times 10 to the power of negative 6 end exponent equals negative fraction numerator 100 over denominator open parentheses 160 plus 40 close parentheses end fraction open parentheses 0 minus B close parentheses cross times pi cross times open parentheses 6 cross times 10 to the power of negative 3 end exponent close parentheses to the power of 2 end exponent cross times cos invisible function application 0 degree$
$rightwards double arrow B equals 0.565 blank T$

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