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Physics

Mechanics

Easy

Question

$text A constant torque acting on a uniform circular disc changes its angular momentum from end text L text to end text fraction numerator 4 L over denominator 3 end fraction text in end text 2 text seconds. Then magnitude of the torque applied is end text$

L/3
2L/3
3L/2
L/6

The correct answer is: L/6

$text Torque end text tau equals fraction numerator d L over denominator d t end fraction equals fraction numerator fraction numerator 4 L over denominator 3 minus L end fraction over denominator 2 end fraction equals L over 6$

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PhysicsMechanics

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PhysicsMechanics

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PhysicsMechanics

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PhysicsMechanics

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