Physics-
General
Easy

Question

A disc is performing pure rolling on a smooth stationary surface with constant angular velocity as shown in figure. At any instant, for the lower most point of the disc.

  1. Velocity is v, acceleration is zero  
  2. Veloity is zero, acceleration is zero  
  3. Velocty is v, acceleration is fraction numerator v to the power of 2 end exponent over denominator R end fraction  
  4. Velocity is zero, acceleration is nonzero  

The correct answer is: Velocity is zero, acceleration is nonzero


    From figure

    Vnet (for lowest point) = v – R = v – v = 0
    and Acceleration = fraction numerator v to the power of 2 end exponent over denominator R end fraction+ O = fraction numerator v to the power of 2 end exponent over denominator R end fraction
    (Since linear speed is constant)
    Hence

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