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Physics-

General

Easy

Question

A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 blank m s to the power of negative 1 end exponent$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $left parenthesis g equals 10 blank m s to the power of negative 2 end exponent right parenthesis$

2 km
0.2 km
20 km
4 km

The correct answer is: 2 km

$t equals square root of fraction numerator 2 cross times 2000 over denominator 10 end fraction end root equals square root of 400 equals 20 blank s$
$x equals 100 m s to the power of negative 1 end exponent cross times 20 s equals 2000 blank m equals 2 k m$

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