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Physics

Fluid-Mechanics

Easy

Question

A horizontal stream of water leaves an opening in the side of a tank. If the opening is y metres above the ground, and the stream hits the ground x metres away. If g is acceleration due to gravity, the speed of water as it leaves the tank in terms of g, y and x is

$x \sqrt{\frac{g}{2 y}}$
$x \sqrt{\frac{2 y}{g}}$
$y \sqrt{\frac{2 y}{g}}$
$y \sqrt{\frac{2 x}{g}}$

The correct answer is: $x square root of fraction numerator g over denominator 2 y end fraction end root$

$x equals u cross times square root of fraction numerator 2 y over denominator g end fraction end root text or end text u equals x square root of fraction numerator g over denominator 2 y end fraction end root$ Range

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