Physics-
General
Easy

Question

A L C circuit is in the state of resonance. If C equals 0.1 mu F and L equals 0.25 blank h e n r y, neglecting ohmic resistance of circuit what is the frequency of oscillations

  1. 1007 blank H z  
  2. 100 blank H z  
  3. 109 blank H z  
  4. 500 blank H z  

The correct answer is: 1007 blank H z


    v subscript 0 end subscript equals fraction numerator 1 over denominator 2 pi square root of left parenthesis 0.25 right parenthesis cross times left parenthesis 0.1 cross times 10 to the power of negative 6 end exponent right parenthesis end root end fraction equals fraction numerator 10 to the power of 4 end exponent over denominator 9.93 end fraction equals 1007 blank H z

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