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Question

A current I equals 10 sin invisible function application left parenthesis 100 blank pi t right parenthesis A is passed in first coil, which induces a maximum emf of 5 blank pi V in second coil. The mutual inductance between the coils is

  1. 5 blank m H  
  2. 10 blank m H  
  3. 15 blank m H  
  4. 20 blank m H  

The correct answer is: 5 blank m H


    e equals negative L fraction numerator d i over denominator d t end fraction semicolon
    fraction numerator d i over denominator d t end fraction equals 10 cross times 100 pi cos invisible function application open parentheses 100 pi t close parentheses
    L equals fraction numerator e over denominator fraction numerator d i over denominator d t end fraction end fraction equals fraction numerator 5 pi over denominator 10 cross times 100 pi end fraction equals 5 cross times 10 to the power of negative 3 end exponent H equals 5 blank m H

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