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Physics

Mechanics

Easy

Question

$A space m o n k e y space o f space m a s s space m space i s space s i t t i n g space o n space a space p l a t f o r m space o f space m a s s space M. space M o n k e y space c a n space j u m p space w i t h space a space v e l o c i t y space o f space 5 space m divided by s space m a k i n g space a n space a n g l e space 370 space w i t h space t h e space h o r i z o n t a l space w i t h space r e s p e c t space t o space p l a t f o r m. space I f space v a l u e space o f space m divided by M space i s space x space ´ space 10 to the power of – 1 end exponent comma space t o space j u m p space t h e space m o n k e y space 1 space m e t e r space w i t h space r e s p e c t space t o space t h e space g r o u n d. space F i n d space o u t space t h e space v a l u e space o f space x$

$x = 14$
$x = 18$
$x = 20$
$x = 11$

The correct answer is: $x equals 14$

$table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell V subscript m M end subscript equals 4 i with not stretchy hat on top plus 3 j with not stretchy hat on top end cell row cell V subscript m equals u i with not stretchy hat on top plus 3 j with not stretchy hat on top end cell row cell V subscript M equals negative V i with not stretchy hat on top end cell end table table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em rowspacing 3 pt end attributes row cell text Here, along horizontal direction end text m V subscript m plus M V subscript M equals 0 end cell row cell not stretchy rightwards double arrow space of 1em V equals fraction numerator u m over denominator M end fraction equals u eta text and end text u plus V equals 4 not stretchy rightwards double arrow u equals fraction numerator 4 over denominator 1 plus eta end fraction end cell end table table attributes columnalign right left right left right left right left right left right left columnspacing 0em 2em 0em 2em 0em 2em 0em 2em 0em 2em 0em rowspacing 3 pt end attributes row cell text To move one meter w.r.t. ground end text end cell row cell 1 equals fraction numerator 2 cross times fraction numerator 4 over denominator 1 plus eta end fraction cross times 3 over denominator g end fraction not stretchy rightwards double arrow 1 plus eta equals 24 over g text or end text eta equals 14 over 10 equals 1.4 equals 14 cross times 10 to the power of negative 1 end exponent end cell row cell therefore space of 1em x equals 14 end cell end table$

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