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Physics-

General

Easy

Question

A non uniform cylinder of mass m, length 1 and radius r is having its centre of mass at a distance 1/4 from the centre and lying on the axis of the cylinder. The cylinder is kept in a liquid of uniform density $rho$ . The moment of inertia of the rod about the centre of mass is I. The angular acceleration of point A relative to point B just after the rod is released from the position shown in figure is

$\frac{π ρ g l^{2} r^{2}}{I}$
$\frac{π ρ g 1^{2} r^{2}}{4 I}$
$\frac{π ρ g l^{2} r^{2}}{2 I}$
$\frac{3 π ρ g l^{2} r^{2}}{4 I}$

The correct answer is: $fraction numerator pi rho g 1 to the power of 2 end exponent r to the power of 2 end exponent over denominator 4 I end fraction$

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