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Physics-

General

Easy

Question

A parallel plate condenser is filled with two dielectrics as shown. Area of each plate is $A m e t r e to the power of 2 end exponent$ and the separation is $t m e t r e$ . The dielectric constants are $k subscript 1 end subscript$ and $k subscript 2 end subscript$ respectively. Its capacitance in farad will be

$\frac{ε_{0} A}{t} (k_{1} + k_{2})$
$\frac{ε_{0} A}{t} . \frac{k_{1} + k_{2}}{2}$
$\frac{2 ε_{0} A}{t} (k_{1} + k_{2})$
$\frac{ε_{0} A}{t} . \frac{k_{1} - k_{2}}{2}$

The correct answer is: $fraction numerator epsilon subscript 0 end subscript A over denominator t end fraction. fraction numerator k subscript 1 end subscript plus k subscript 2 end subscript over denominator 2 end fraction$

The two capacitors are in parallel so $C equals fraction numerator epsilon subscript 0 end subscript A over denominator t cross times 2 end fraction left parenthesis k subscript 1 end subscript plus k subscript 2 end subscript right parenthesis$

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