Physics-
General
Easy

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 blank c m divided by s. The frequency of its oscillation is

  1. 3 Hz    
  2. 2 Hz    
  3. 4 Hz    
  4. 1 Hz    

The correct answer is: 1 Hz


    A equals 5 cm
    V subscript m a n end subscript equals 3.14 blank c m divided by s
    rightwards double arrow A omega equals 31.4
    rightwards double arrow omega equals fraction numerator 31.4 over denominator 5 end fraction
    rightwards double arrow 2 pi v equals fraction numerator 31.4 over denominator 5 end fraction
    rightwards double arrow v equals fraction numerator 31.4 over denominator 2 cross times 3.14 cross times 5 end fraction = 1 Hz

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