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Question

A particle is thrown vertically upwards. If it velocity at half of the maximum height is 10 blank m divided by s e c, then maximum height attained by it is (Take g equals 10 blank m divided by sec to the power of 2 end exponent invisible function application blank)

  1. 8 blank m  
  2. 10 blank m  
  3. 12 blank m  
  4. 16 blank m  

The correct answer is: 10 blank m


    Let particle thrown with velocity u and its maximum height is H then H equals fraction numerator u to the power of 2 end exponent over denominator 2 g end fraction
    When particle is at height H divided by 2, then its speed is 10 blank m divided by s
    From equation v to the power of 2 end exponent equals u to the power of 2 end exponent minus 2 g h
    open parentheses 10 close parentheses to the power of 2 end exponent equals u to the power of 2 end exponent minus 2 g open parentheses fraction numerator H over denominator 2 end fraction close parentheses equals u to the power of 2 end exponent minus 2 g fraction numerator u to the power of 2 end exponent over denominator 4 g end fraction blank rightwards double arrow u to the power of 2 end exponent equals 200
    Maximum height rightwards double arrow H equals fraction numerator u to the power of 2 end exponent over denominator 2 g end fraction equals fraction numerator 200 over denominator 2 cross times 10 end fraction equals 10 blank m

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