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Question

A particle moves in a circle of radius 5 blank c m with constant speed and time period 0.2 blank pi s. The acceleration of the particle is

  1. 5 blank m divided by s to the power of 2 end exponent  
  2. 15 blank m divided by s to the power of 2 end exponent  
  3. 25 blank m divided by s to the power of 2 end exponent  
  4. 36 blank m divided by s to the power of 2 end exponent  

The correct answer is: 5 blank m divided by s to the power of 2 end exponent


    a equals omega to the power of 2 end exponent R equals open parentheses fraction numerator 2 pi over denominator 0.2 pi end fraction close parentheses to the power of 2 end exponent open parentheses 5 cross times 10 to the power of negative 2 end exponent close parentheses equals 5 blank m divided by s to the power of 2 end exponent

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