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Question

A projectile is thrown at angle beta with vertical. It reaches a maximum height H. The time taken to reach the highest point of its path is

  1. square root of fraction numerator H over denominator g end fraction end root  
  2. square root of fraction numerator 2 H over denominator g end fraction end root  
  3. square root of fraction numerator H over denominator 2 g end fraction end root  
  4. square root of fraction numerator H over denominator g cos invisible function application beta end fraction end root  

The correct answer is: square root of fraction numerator 2 H over denominator g end fraction end root


    M a x i m u m blank h e i g h t blank H equals fraction numerator v to the power of 2 end exponent c o s to the power of 2 end exponent beta over denominator 2 g end fraction
    o r blank v c o s beta equals square root of 2 g H end root
    t equals fraction numerator v c o s beta over denominator g end fraction equals fraction numerator square root of 2 g H end root over denominator g end fraction
    t equals square root of fraction numerator 2 H over denominator g end fraction end root

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